Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Electromagnetic Induction

JEE Main 2026 (Online) 22nd January Evening ShiftNumericalMedium📈 Topic in 5% papers+4
Ques. 1JEE Main 2026, 22 January (Evening Shift)

A conducting circular loop is rotated about its diameter at a constant angular speed of 100 rad/s in a magnetic field of 0.5 T perpendicular to the axis of rotation. When the loop is rotated by 30 from the horizontal position, the induced EMF is 15.4 mV. The radius of the loop is mm. (Take = 227)

Answer

14

Solution

In the horizontal position the field is along the normal to the loop (maximum flux, zero EMF). After it turns through = t, = BA t, so

e = - d dt = BA t

At t = 30 , e = B( r2) 30 , so

15.4 10-3 = 0.5 227r2 100 12

r2 = 15.4 10-3 725 22 = 1.96 10-4 m2

r = 1.4 10-2 m

r = 14 mm

Answer: 14

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2026, 21 January (Morning Shift)

A conducting circular loop of area 1.0 m2 is placed perpendicular to a magnetic field which varies as B = (100t) Tesla. If the resistance of the loop is 100 , then the average thermal energy dissipated in the loop in one period is J.

  1. 2
  2. 2
  3. 2
Ques. 3JEE Main 2026, 21 January (Morning Shift)

A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is N. [figure]

  1. 5.7 10-2
  2. 7.5 10-3
  3. 5.7 10-3
  4. 7.5 10-2
Ques. 4JEE Main 2025, 4 April (Morning Shift)

Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1 2 Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of 10 cm/s, induced emf between points A and E is mV. [figure]

Ques. 5JEE Main 2025, 2 April (Evening Shift)

A solenoid having area A and length 'l' is filled with a material having relative permeability 2. The magnetic energy stored in the solenoid is :

  1. B2Al4 0
  2. B2Al2 0
  3. B2Al 0
  4. B2Al
Ques. 6JEE Main 2025, 29 January (Morning Shift)

A coil of area A and N turns is rotating with angular velocity in a uniform magnetic field B about an axis perpendicular to B. Magnetic flux and induced emf across it, at an instant when B is parallel to the plane of coil, are :

  1. = AB, = NAB
  2. = AB, = 0
  3. = 0, = 0
  4. = 0, = NAB
Ques. 7JEE Main 2025, 29 January (Morning Shift)

Consider I1 and I2 are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L1 = self inductance of coil 1, M12 = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be :

  1. e1 = -L1 dI2dt - M12 dI1dt
  2. e1 = -L1 dI1dt + M12 dI2dt
  3. e1 = -L1 dI1dt - M12 dI1dt
  4. e1 = -L1 dI1dt - M12 dI2dt
Ques. 8JEE Main 2025, 28 January (Evening Shift)

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? ( = 3.14)

  1. 0.5024 V
  2. 0.0628 V
  3. 0.2512 V
  4. 0.1256 V
Ques. 9JEE Main 2025, 28 January (Evening Shift)

[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .

Ques. 10JEE Main 2025, 23 January (Morning Shift)

Regarding self-inductance: Choose the correct answer from the options given below:

  1. A, B, C, E only
  2. A, B, C, D only
  3. A, C, D, E only
  4. B, C, D, E only
Ques. 11JEE Main 2025, 23 January (Morning Shift)

[figure] In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 , the value of the current in the circuit will be A.

All Electromagnetic Induction PYQs →

PDFDownload Electromagnetic Induction PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters