Electromagnetic Induction

JEE Main 2025 (Online) 28th January Evening ShiftMCQEasy📈 Topic in 18% papers+4−1

Ques. 1JEE Main 2025, 28 January (Evening Shift)

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? ( = 3.14)

0.5024 V
0.0628 V
0.2512 V
0.1256 V

Answer

(3) 0.2512 V

Solution

An element dr at distance r moves with speed r:

d = B( r) dr

= 0R B r dr = 12B R2

= 12 0.4 10 (0.2)2

= 0.08 = 0.08 3.14 = 0.2512 V

Answer: (3)

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2025, 28 January (Evening Shift)

[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .

Ques. 3JEE Main 2025, 23 January (Morning Shift)

Regarding self-inductance: Choose the correct answer from the options given below:

A, B, C, E only
A, B, C, D only
A, C, D, E only
B, C, D, E only

Ques. 4JEE Main 2025, 23 January (Morning Shift)

[figure] In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 , the value of the current in the circuit will be A.

Ques. 5JEE Main 2025, 22 January (Evening Shift)

A rectangular metallic loop is moving out of a uniform magnetic field region to a field free region with a constant speed. When the loop is partially inside the magnetic field, the plot of magnitude of induced emf ( ) with time (t) is given by

[figure]
[figure]
[figure]
[figure]

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