Electromagnetic Induction

JEE Main 2025 (Online) 23rd January Morning ShiftNumericalMedium📈 Topic in 5% papers+4

Ques. 1JEE Main 2025, 23 January (Morning Shift)

[figure] In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 , the value of the current in the circuit will be A.

Answer

Solution

Pulling the contact out raises R, so I falls ( dIdt=-8 A s-1 ); the inductor opposes the fall, so its emf aids the cell.

[figure]

12-L dIdt=IR 12+3(8)=12I

I= 3612=3 A

Answer: 3

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2025, 22 January (Evening Shift)

A rectangular metallic loop is moving out of a uniform magnetic field region to a field free region with a constant speed. When the loop is partially inside the magnetic field, the plot of magnitude of induced emf ( ) with time (t) is given by

[figure]
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