Electromagnetic Induction

JEE Main 2025 (Online) 28th January Evening ShiftNumericalMedium📈 Topic in 18% papers+4

Ques. 1JEE Main 2025, 28 January (Evening Shift)

[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .

Answer

Solution

Let each rail make an angle θ with the direction of motion, and the bar move with constant speed v.

Distance from the vertex at time t: y = vt

Length of bar between the rails: L = 2y = 2vt

Induced emf: E = BLv = 2Bv2 t

E t1 n = 1

Answer: 1

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2025, 23 January (Morning Shift)

Regarding self-inductance: Choose the correct answer from the options given below:

A, B, C, E only
A, B, C, D only
A, C, D, E only
B, C, D, E only

Ques. 3JEE Main 2025, 23 January (Morning Shift)

[figure] In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 , the value of the current in the circuit will be A.

Ques. 4JEE Main 2025, 22 January (Evening Shift)

A rectangular metallic loop is moving out of a uniform magnetic field region to a field free region with a constant speed. When the loop is partially inside the magnetic field, the plot of magnitude of induced emf ( ) with time (t) is given by

[figure]
[figure]
[figure]
[figure]

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