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Electromagnetic Induction

JEE Main 2026 (Online) 21st January Morning ShiftMCQEasy📈 Topic in 22% papers+4−1
Ques. 1JEE Main 2026, 21 January (Morning Shift)

A 1 m long metal rod AB completes the circuit as shown in figure. The area of circuit is perpendicular to the magnetic field of 0.10 T. If the resistance of the total circuit is 2 then the force needed to move the rod towards right with constant speed (v) of 1.5 m/s is N. [figure]

  1. 5.7 10-2
  2. 7.5 10-3
  3. 5.7 10-3
  4. 7.5 10-2

Answer

(2) 7.5 10-3

Solution

Motional emf in the rod: = Bvl = 0.10 1.5 1 = 0.15 V

Current: I = R = 0.152 = 0.075 A

Magnetic force on the rod (opposes the motion): FB = BIl = 0.10 0.075 1 = 7.5 10-3 N

For constant speed, the applied force balances FB.

F = 7.5 10-3 N

Answer: (2)

Keep practising — Electromagnetic Induction

Ques. 2JEE Main 2025, 4 April (Morning Shift)

Conductor wire ABCDE with each arm 10 cm in length is placed in magnetic field of 1 2 Tesla, perpendicular to its plane. When conductor is pulled towards right with constant velocity of 10 cm/s, induced emf between points A and E is mV. [figure]

Ques. 3JEE Main 2025, 2 April (Evening Shift)

A solenoid having area A and length 'l' is filled with a material having relative permeability 2. The magnetic energy stored in the solenoid is :

  1. B2Al4 0
  2. B2Al2 0
  3. B2Al 0
  4. B2Al
Ques. 4JEE Main 2025, 29 January (Morning Shift)

A coil of area A and N turns is rotating with angular velocity in a uniform magnetic field B about an axis perpendicular to B. Magnetic flux and induced emf across it, at an instant when B is parallel to the plane of coil, are :

  1. = AB, = NAB
  2. = AB, = 0
  3. = 0, = 0
  4. = 0, = NAB
Ques. 5JEE Main 2025, 29 January (Morning Shift)

Consider I1 and I2 are the currents flowing simultaneously in two nearby coils 1 & 2, respectively. If L1 = self inductance of coil 1, M12 = mutual inductance of coil 1 with respect to coil 2, then the value of induced emf in coil 1 will be :

  1. e1 = -L1 dI2dt - M12 dI1dt
  2. e1 = -L1 dI1dt + M12 dI2dt
  3. e1 = -L1 dI1dt - M12 dI1dt
  4. e1 = -L1 dI1dt - M12 dI2dt
Ques. 6JEE Main 2025, 28 January (Evening Shift)

A uniform magnetic field of 0.4 T acts perpendicular to a circular copper disc 20 cm in radius. The disc is having a uniform angular velocity of 10 rad s-1 about an axis through its centre and perpendicular to the disc. What is the potential difference developed between the axis of the disc and the rim? ( = 3.14)

  1. 0.5024 V
  2. 0.0628 V
  3. 0.2512 V
  4. 0.1256 V
Ques. 7JEE Main 2025, 28 January (Evening Shift)

[figure] A conducting bar moves on two conducting rails as shown in the figure. A constant magnetic field B exists into the page. The bar starts to move from the vertex at time t = 0 with a constant velocity. If the induced EMF is E tn, then value of n is .

Ques. 8JEE Main 2025, 23 January (Morning Shift)

Regarding self-inductance: Choose the correct answer from the options given below:

  1. A, B, C, E only
  2. A, B, C, D only
  3. A, C, D, E only
  4. B, C, D, E only
Ques. 9JEE Main 2025, 23 January (Morning Shift)

[figure] In the given circuit the sliding contact is pulled outwards such that electric current in the circuit changes at the rate of 8 A/s. At an instant when R is 12 , the value of the current in the circuit will be A.

Ques. 10JEE Main 2025, 22 January (Evening Shift)

A rectangular metallic loop is moving out of a uniform magnetic field region to a field free region with a constant speed. When the loop is partially inside the magnetic field, the plot of magnitude of induced emf ( ) with time (t) is given by

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 11JEE Main 2024, 9 April (Evening Shift)

A square loop of side 15 cm is being moved towards right at a constant speed of 2 cm/s as shown in figure. The front edge enters the 50 cm wide magnetic field at t = 0. The value of induced emf in the loop at t = 10 s will be : [figure]

  1. zero
  2. 4.5 mV
  3. 0.3 mV
  4. 3 mV

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