Inductance of a coil with 104 turns per metre is 10 mH and it is connected to a dc source of 10 V with internal resistance of 10 . The energy density in the inductor when the current reaches ( 1e ) of its maximum value is 1e2 J/m3. The value of is . ( 0 = 4 10-7 T m/A).
Answer
20
Solution
The maximum (steady) current is Imax = Vr = 1010 = 1 A, so the required current is I = Imaxe = 1e A.
The field inside the coil (long solenoid, n turns per unit length) is B = 0 n I, so the energy density is
u = B22 0 = 12 0 n2 I2
u = 12 4 10-7 (104)2 1e2
u = 2 10-7 108 1e2
u = 20 1e2 J/m3
= 20
Answer: 20