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Principles of Inheritance and Variation

Previous year questions with solutions · 2000 – 2026

168Questions
34Papers covered
8.91%Weightage 2026▲ 60.4% vs last year
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Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
2026924.58.91% ▲ 60.4% vs last year
20253135.56% ▼ 47.2% vs last year
2024122610.53% ▲ 32.6% vs last year
20235157.94% ▼ 13.4% vs last year
202212269.16% ▲ 174.8% vs last year
20212123.33% ▼ 58.3% vs last year
20204148.00% ▼ 15.2% vs last year
20195159.43% ▲ 29.7% vs last year
20184147.27% ▼ 17.1% vs last year
20175158.77% ▲ 12.1% vs last year
2016924.57.83% ▲ 42.2% vs last year
20156235.50% ▼ 23.6% vs last year
20138247.21% ▲ 48.5% vs last year
2012522.54.85% ▲ 16.5% vs last year
20114224.17% ▼ 58.3% vs last year
2010924.510.00% ▲ 40% vs last year
20094147.14% ▲ 96.4% vs last year
20082123.64% ▼ 62.9% vs last year
20075159.80% ▼ 35.7% vs last year
200691915.25% ▲ 20.1% vs last year
200581812.70% ▼ 12.7% vs last year
200481814.55% ▲ 12.7% vs last year
200381812.90% ▲ 3.2% vs last year
200281812.50% ▼ 18.1% vs last year
200191915.25% ▲ 64.7% vs last year
20005159.26%

⚠ 1 of these questions are out of the current syllabus (marked on the question).

168 questions · newest paper first · page 4 of 6

Ques. 91AIPMT 2011 (Mains)

Test cross in plants or in Drosophila involves crossing:

  1. the F1 hybrid with a double recessive genotype
  2. between two genotypes with dominant trait
  3. between two F1 hybrids
  4. between two genotypes with recessive trait
Ques. 92AIPMT 2011 (Prelims)

Which one of the following conditions correctly describes the manner of determining the sex ?

  1. XO condition in humans as found in Turner Syndrome, determines female sex
  2. XO type of sex chromosomes determine male sex in grasshopper
  3. Homozygous sex chromosomes (ZZ) determine female sex in Birds
  4. Homozygous sex chromosomes (XX) produce male in Drosophila
Ques. 93AIPMT 2011 (Prelims)

Mutations can be induced with :

  1. Gamma radiation
  2. Infra Red radiations
  3. IAA
  4. Ethylene
Ques. 94AIPMT 2010 (Mains)

ABO blood grouping is controlled by gene I which has three alleles and shows co-dominance. There are six genotypes. How many phenotypes in all are possible -

  1. five
  2. four
  3. three
  4. six
Ques. 95AIPMT 2010 (Mains)

Study the pedigree chart of a certain family given below and select the correct conclusion which can be drawn for the character – [figure]

  1. The trait under study could not be colourblindness
  2. The female parent is heterozygous
  3. The parents could not have had a normal daughter for this character
  4. The male parent is homozygous dominant
Ques. 96AIPMT 2010 (Mains)

A cross in which an organism showing a dominant phenotype is crossed with the recessive parent in order to know its genotype is called -

  1. Dihybrid cross
  2. Back cross
  3. Monohybrid cross
  4. Test cross
Ques. 97AIPMT 2010 (Mains)

In Antirrhinum two plants with pink flowers were hybridized. The F1 plants produced red, pink and white flowers in the proportion of 1 red, 2 pink and 1 white. What could be the genotype of the two plants used for hybridization? Red flower colour is determined by RR, and White by rr genes -

  1. rrrr
  2. rr
  3. Rr
  4. RR
Ques. 98AIPMT 2010 (Prelims)

Which one of the following symbols and its representation, used in human pedigree analysis is correct –

  1. [figure] = mating between relatives
  2. [figure] = unaffected female
  3. [figure] = unaffected male
  4. [figure] = male affected
Ques. 99AIPMT 2010 (Prelims)

ABO blood groups in humans are controlled by the gene I. It has three alleles – IA, IB and i. Since there are three different alleles, six different genotypes are possible. How many phenotypes can occur –

  1. One
  2. Two
  3. Three
  4. Four
Ques. 100AIPMT 2010 (Prelims)

Select the correct statement from the ones given below with respect to dihybrid cross –

  1. Genes far apart on the same chromosome show very few recombinations
  2. Tightly linked genes on the same chromosome show very few recombinations
  3. Tightly linked genes on the same chromosome show higher recombinations
  4. Genes loosely linked on the same chromosome show similar recombinations as the tightly linked ones
Ques. 101AIPMT 2010 (Prelims)

The genotype of a plant showing the dominant phenotype can be determined by –

  1. Pedigree analysis
  2. Back cross
  3. Test cross
  4. Dihybrid cross
Ques. 102AIPMT 2010 (Prelims)

Which one of the following cannot be explained on the basis of Mendel's Law of Dominance?

  1. Out of one pair of factors one is dominant, and the other recessive
  2. Alleles do not show any blending and both the characters recover as such in F2 generation
  3. The discrete unit controlling a particular character is called a factor
  4. Factors occur in pairs
Ques. 103AIPMT 2009

Select the incorrect statement from the following:

  1. Baldness is a sex limited trait
  2. Galactosemia is an inborn error of metabolism
  3. Linkage is an exception to the principle of independent assortment in heredity
  4. Small population size results in random genetic drift in a population
Ques. 104AIPMT 2009

Sickle-cell anaemia is:

  1. Caused by substitution of valine by glutamic acid in the beta globin chain of haemoglobin
  2. An autosomal linked dominant trait
  3. Caused by a change in a single base pair of DNA
  4. Characterised by elongated sickle like RBCs with a nucleus
Ques. 105AIPMT 2009

The most popularly known blood grouping is the ABO grouping. It is named ABO and not ABC, because "O" in it refers to having:

  1. Other antigens besides A and B on RBCs
  2. No antigens A and B on RBCs
  3. Overdominance of this type on the genes for A and B types
  4. One antibody only – either anti-A or anti-B on the RBCs
Ques. 106AIPMT 2009

Study the pedigree chart given below: [figure] What does it show?

  1. Inheritance of a recessive sex-linked disease like haemophilia
  2. Inheritance of a sex-linked inborn error of metabolism like phenylketonuria
  3. The pedigree chart is wrong as this is not possible
  4. Inheritance of a condition like phenylketonuria as an autosomal recessive trait
Ques. 107AIPMT 2008

Which one of the following conditions in humans is correctly matched with its chromosomal abnormality/linkage?

  1. Klinefelter's syndrome — 44 autosomes + XXY
  2. Colour-blindness — Y-linked
  3. Down syndrome — 44 autosomes + XO
  4. Erythroblastosis foetalis — X-linked
Ques. 108AIPMT 2008

Haploids are more suitable for mutation studies than the diploids. This is because:

  1. all mutations, whether dominant or recessive are expressed in haploids
  2. mutagens penetrate in haploids more effectively than in diploids
  3. haploids are reproductively more stable than diploids
  4. haploids are more abundant in nature than diploids
Ques. 109AIPMT 2007

A human male produces sperms with the genotypes AB, Ab, aB, and ab pertaining to two diallelic characters in equal proportions. What is the corresponding genotype of this person?

  1. AaBb
  2. AABB
  3. AaBB
  4. AABb
Ques. 110AIPMT 2007

In pea plants, yellow seeds are dominant to green. If a heterozygous yellow seeded plant is crossed with a green seeded plant, what ratio of yellow and green seeded plants would you expect in F1 generation?

  1. 9 : 1
  2. 3 : 1
  3. 50 : 50
  4. 1 : 3
Ques. 111AIPMT 2007

Inheritance of skin colour in humans is an example of:

  1. Chromosomal aberration
  2. Polygenic inheritance
  3. Codominance
  4. Point mutation
Ques. 112AIPMT 2007

In the hexaploid wheat, the haploid (n) and basic (x) numbers of chromosomes are:

  1. n = 21 and x = 14
  2. n = 21 and x = 21
  3. n = 7 and x = 21
  4. n = 21 and x = 7
Ques. 113AIPMT 2007

A common test to find the genotype of a hybrid is by:-

  1. Crossing of one F1 progeny with recessive parent
  2. Crossing of one F2 progeny with female parent
  3. Crossing of one F2 progeny with male parent
  4. Studying the sexual behaviour of F1 progenies
Ques. 114AIPMT 2006

Both sickle cell anemia and Huntington's chorea are-

  1. Congenital disorders
  2. Bacteria-related diseases
  3. Virus-related diseases
  4. Pollutant-induced disorders
Ques. 115AIPMT 2006

Test cross involves-

  1. Crossing between two F1 hybrids
  2. Crossing the F1 hybrid with a double recessive genotype
  3. Crossing between two genotypes with recessive trait
  4. Crossing between two genotypes with dominant trait
Ques. 116AIPMT 2006

If a colour blind woman marries a normal visioned man, their sons will be

  1. All normal visioned
  2. Three-fourths colourblind and one-fourth normal
  3. One-half colourblind and one-half normal
  4. All colourblind
Ques. 117AIPMT 2006

Cri-du-chat syndrome in humans is caused by the-

  1. Loss of half of the long arm of chromosome 5
  2. Loss of half of the short arm of chromosome 5
  3. Trisomy of 21st chromosome
  4. Fertilization of an XX egg by a normal Y-bearing sperm
Ques. 118AIPMT 2006

Sickle cell anaemia has not been eliminated from the African population because-

  1. It is not a fatal disease
  2. It is controlled by dominant genes
  3. It is controlled by recessive genes
  4. It provides immunity against malaria
Ques. 119AIPMT 2006

In Mendel's experiments with garden pea, round seed shape (RR) was dominant over wrinkled seeds (rr), yellow cotyledon (YY) was dominant over green cotyledon (yy). What are the expected phenotypes in the F2 generation of the cross RRYY × rryy?

  1. Round seeds with yellow cotyledons, and wrinkled seeds with yellow cotyledons
  2. Only wrinkled seeds with green cotyledons
  3. Only wrinkled seeds with yellow cotyledons
  4. Only round seeds with green cotyledons
Ques. 120AIPMT 2006

How many different kinds of gametes will be produced by a plant having the genotype AABbCC?

  1. Two
  2. Nine
  3. Four
  4. Three