How many different kinds of gametes will be produced by a plant having the genotype AABbCC?
- Two
- Nine
- Four
- Three
Answer
(1) Two
Solution
The number of kinds of gametes is 2n, where n is the number of heterozygous gene pairs.
In AABbCC only Bb is heterozygous (AA and CC are homozygous), so n = 1 and
Number of gametes = 21 = 2, namely ABC and AbC.
Answer: (1)