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Principles of Inheritance and Variation

AIPMT 2005MCQEasy📈 Topic in 50% papers+4−1
Ques. 1AIPMT 2005

G-6-P dehydrogenase deficiency is associated with haemolysis of -

  1. RBCs
  2. Lymphocytes
  3. Platelets
  4. Leucocytes

Answer

(1) RBCs

Solution

Glucose-6-phosphate dehydrogenase (G-6-PD) deficiency is an X-linked recessive inborn error of metabolism.

G-6-PD produces NADPH in red blood cells, and NADPH keeps glutathione reduced and protects the RBC membrane from oxidative damage. In its absence (e.g., after eating fava beans or taking certain drugs), the RBCs rupture.

∴ The deficiency causes haemolysis of RBCs (haemolytic anaemia).

Answer: (1)

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Ques. 2AIPMT 2005

A man and a woman, who do not show any apparent signs of a certain inherited disease, have seven children (2 daughters and 5 sons). Three of the sons suffer from the given disease but none of the daughters are affected. Which of the following mode of inheritance do you suggest for this disease?

  1. Autosomal dominant
  2. Sex-linked recessive
  3. Sex-linked dominant
  4. Sex-limited recessive
Ques. 3AIPMT 2005

A woman with 47 chromosomes due to three copies of chromosome 21 is characterized by -

  1. Superfemaleness
  2. Turner's syndrome
  3. Triploidy
  4. Down's syndrome
Ques. 4AIPMT 2005

Haemophilia is more commonly seen in human males than in human females because -

  1. This disease is due to an X-linked dominant mutation
  2. This disease is due to a Y-linked recessive mutation
  3. This disease is due to an X-linked recessive mutation
  4. A greater proportion of girls die in infancy
Ques. 5AIPMT 2005

Which of the following is not a hereditary disease?

  1. Cretinism
  2. Cystic fibrosis
  3. Haemophilia
  4. Thalassemia
Ques. 6AIPMT 2005

A woman with normal vision, but whose father was colour blind, marries a colour blind man. Suppose that the fourth child of this couple was a boy. This boy -

  1. May be colour blind or may have normal vision
  2. Must have normal colour vision
  3. Must be colour blind
  4. Will be partially colour blind since he is heterozygous for the colour blind mutant allele.
Ques. 7AIPMT 2005

A woman with 47 chromosomes due to three copies of chromosome 21 is characterized by

  1. triploidy
  2. Down’s syndrome
  3. superfemaleness
  4. Turner’s syndrome
Ques. 8AIPMT 2004

In a plant, red fruit (R) is dominant over yellow fruit (r) and tallness (T) is dominant over shortness (t). If a plant with RRTt genotype is crossed with a plant that is rrtt

  1. 75% will be tall with red fruit
  2. 25% will be tall with red fruit
  3. 50% will be tall with red fruit
  4. All the offspring will be tall with red fruit
Ques. 9AIPMT 2004

A male human is heterozygous for autosomal genes A and B and is also hemizygous for hemophilic gene h. What proportion of his sperms will be abh?

  1. 1/16
  2. 1/32
  3. 1/8
  4. 1/4
Ques. 10AIPMT 2004

Lack of independent assortment of two genes A and B in fruit fly Drosophila is due to

  1. Linkage
  2. Recombination
  3. Repulsion
  4. Crossing over
Ques. 11AIPMT 2004

One of the parents of a cross has a mutation in its mitochondria. In that cross, that parent is taken as a male. During segregation of F2 progenies that mutation is found in -

  1. 50% of the progenies
  2. 1/3 of the progenies
  3. None of the progenies
  4. All the progenies

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