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Amines

JEE Main 2025 (Online) 4th April Morning ShiftMCQEasy📈 Topic in 39% papers+4−1
Ques. 1JEE Main 2025, 4 April (Morning Shift)

The major product (A) formed in the following reaction sequence is [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(2) [figure]

Solution

(i) Sn/HCl reduces -NO2 to -NH2 (aniline).

(ii) Ac2O/pyridine acetylates it to acetanilide; the lone pair on N is now also in resonance with C=O, so -NHCOCH3 is only a moderately activating o/p-director.

(iii) Br2/AcOH gives mainly the para-bromo product (ortho is hindered by the bulky group).

(iv) aqueous NaOH hydrolyses the amide back to the free amine.

[figure]

A is 4-bromoaniline.

Answer: (2)

Keep practising — Amines

Ques. 2JEE Main 2025, 3 April (Morning Shift)

Identify [A], [B] and [C], respectively in the following reaction sequence : [figure]

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 3JEE Main 2025, 3 April (Morning Shift)

In the following reactions, which one is NOT correct?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2025, 3 April (Evening Shift)

The sequence from the following that would result in giving predominantly 3,4,5-Tribromoaniline is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 5JEE Main 2025, 2 April (Morning Shift)

The correct order of basic nature in aqueous solution for the bases NH3, H2N-NH2, CH3CH2NH2, (CH3CH2)2NH and (CH3CH2)3N is :

  1. NH3 < H2N-NH2 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  2. H2N-NH2 < NH3 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  3. H2N-NH2 < NH3 < CH3CH2NH2 < (CH3CH2)3N < (CH3CH2)2NH
  4. NH3 < H2N-NH2 < CH3CH2NH2 < (CH3CH2)2NH < (CH3CH2)3N
Ques. 6JEE Main 2025, 2 April (Evening Shift)

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, S : 32)

  1. 330
  2. 33
  3. 343
  4. 66
Ques. 7JEE Main 2025, 29 January (Morning Shift)

Given below are some nitrogen containing compounds : [figure] Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume mg of HCl. (Given molar mass in g mol-1 C : 12, H : 1, O : 16, Cl : 35.5)

Ques. 8JEE Main 2025, 29 January (Evening Shift)

Which one of the following reaction sequences will give an azo dye?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 9JEE Main 2025, 28 January (Morning Shift)

Consider the following sequence of reactions: [figure] 11.25 mg of chlorobenzene will produce 10-1 mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol-1 respectively]

Ques. 10JEE Main 2025, 28 January (Evening Shift)

Identify correct statements : Choose the correct answer from the options given below :

  1. (B) and (C) only
  2. (D) and (E) only
  3. (A) and (B) only
  4. (B) and (D) only
Ques. 11JEE Main 2025, 24 January (Evening Shift)

For reaction [figure] The correct order of set of reagents for the above conversion is :

  1. Ac2O, Br2, H2O( ), NaOH
  2. H2SO4, Ac2O, Br2, H2O( ), NaOH
  3. Br2 | FeBr3, H2O( ), NaOH
  4. Ac2O, H2SO4, Br2, NaOH

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