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Amines

JEE Main 2025 (Online) 3rd April Morning ShiftMCQEasy📈 Topic in 21% papers+4−1
Ques. 1JEE Main 2025, 3 April (Morning Shift)

In the following reactions, which one is NOT correct?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(3) [figure]

Solution

(1) Correct. Hypophosphorous acid reduces the diazonium salt to benzene:

C6H5N2+Cl- + H3PO2 + H2O C6H6 + N2 + H3PO3 + HCl

(2) Correct. Sandmeyer reaction: CuCN/KCN replaces the diazo group by –CN, giving benzonitrile.

(3) NOT correct. As per NCERT, ethanol is a mild reducing agent: it reduces the diazonium salt to benzene and is itself oxidised to ethanal; ethoxybenzene is not formed.

C6H5N2+Cl- + CH3CH2OH C6H6 + N2 + CH3CHO + HCl

(4) Correct. Iodide ion replaces the diazo group directly, giving iodobenzene.

Answer: (3)

Keep practising — Amines

Ques. 2JEE Main 2025, 3 April (Evening Shift)

The sequence from the following that would result in giving predominantly 3,4,5-Tribromoaniline is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 3JEE Main 2025, 2 April (Morning Shift)

The correct order of basic nature in aqueous solution for the bases NH3, H2N-NH2, CH3CH2NH2, (CH3CH2)2NH and (CH3CH2)3N is :

  1. NH3 < H2N-NH2 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  2. H2N-NH2 < NH3 < (CH3CH2)3N < CH3CH2NH2 < (CH3CH2)2NH
  3. H2N-NH2 < NH3 < CH3CH2NH2 < (CH3CH2)3N < (CH3CH2)2NH
  4. NH3 < H2N-NH2 < CH3CH2NH2 < (CH3CH2)2NH < (CH3CH2)3N
Ques. 4JEE Main 2025, 2 April (Evening Shift)

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, S : 32)

  1. 330
  2. 33
  3. 343
  4. 66
Ques. 5JEE Main 2025, 29 January (Morning Shift)

Given below are some nitrogen containing compounds : [figure] Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume mg of HCl. (Given molar mass in g mol-1 C : 12, H : 1, O : 16, Cl : 35.5)

Ques. 6JEE Main 2025, 29 January (Evening Shift)

Which one of the following reaction sequences will give an azo dye?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 7JEE Main 2025, 28 January (Morning Shift)

Consider the following sequence of reactions: [figure] 11.25 mg of chlorobenzene will produce 10-1 mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol-1 respectively]

Ques. 8JEE Main 2025, 28 January (Evening Shift)

Identify correct statements : Choose the correct answer from the options given below :

  1. (B) and (C) only
  2. (D) and (E) only
  3. (A) and (B) only
  4. (B) and (D) only
Ques. 9JEE Main 2025, 24 January (Evening Shift)

For reaction [figure] The correct order of set of reagents for the above conversion is :

  1. Ac2O, Br2, H2O( ), NaOH
  2. H2SO4, Ac2O, Br2, H2O( ), NaOH
  3. Br2 | FeBr3, H2O( ), NaOH
  4. Ac2O, H2SO4, Br2, NaOH
Ques. 10JEE Main 2025, 23 January (Morning Shift)

Which among the following react with Hinsberg's reagent? Choose the correct answer from the options given below :

  1. A, C and E only
  2. A, B and E only
  3. C and D only
  4. B and D only
Ques. 11JEE Main 2025, 23 January (Morning Shift)

Consider the following sequence of reactions to produce major product (A) [figure] Molar mass of product (A) is g mol-1. (Given molar mass in g mol-1 of C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31)

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