Amines

When a concentrated solution of sulphanilic acid and 1-naphthylamine is treated with nitrous acid (273 K) and acidified with acetic acid, the mass (g) of 0.1 mole of product formed is: (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, S : 32)

1. 330
2. 33
3. 343
4. 66

Given below are some nitrogen containing compounds : [figure] Each of them is treated with HCl separately. 1.0 g of the most basic compound will consume mg of HCl. (Given molar mass in g mol-1 C : 12, H : 1, O : 16, Cl : 35.5)

Which one of the following reaction sequences will give an azo dye?

1. [figure]
2. [figure]
3. [figure]
4. [figure]

Consider the following sequence of reactions: [figure] 11.25 mg of chlorobenzene will produce 10-1 mg of product B. (Consider the reactions result in complete conversion.) [Given molar mass of C, H, O, N and Cl as 12, 1, 16, 14 and 35.5 g mol-1 respectively]

Identify correct statements : Choose the correct answer from the options given below :

1. (B) and (C) only
2. (D) and (E) only
3. (A) and (B) only
4. (B) and (D) only

For reaction [figure] The correct order of set of reagents for the above conversion is :

1. Ac2O, Br2, H2O( ), NaOH
2. H2SO4, Ac2O, Br2, H2O( ), NaOH
3. Br2 | FeBr3, H2O( ), NaOH
4. Ac2O, H2SO4, Br2, NaOH

Which among the following react with Hinsberg's reagent? Choose the correct answer from the options given below :

1. A, C and E only
2. A, B and E only
3. C and D only
4. B and D only

Consider the following sequence of reactions to produce major product (A) [figure] Molar mass of product (A) is g mol-1. (Given molar mass in g mol-1 of C : 12, H : 1, O : 16, Br : 80, N : 14, P : 31)

Consider the following sequence of reactions. [figure] Total number of sp3 hybridised carbon atoms in the major product C formed is .

The products formed in the following reaction sequence are : [figure]

1. [figure]
2. [figure]
3. [figure]
4. [figure]