The molar solubility(s) of zirconium phosphate with molecular formula ( Zr4+ )3 ( PO43- )4 is given by relation :
- ( Ksp5348 )1/6
- ( Ksp8435 )1/7
- ( Ksp6912 )1/7
- ( Ksp9612 )1/3
Answer
(3) ( Ksp6912 )1/7
Solution
Zr3(PO4)4 3Zr4+ + 4PO43- ⇒ [ Zr4+]=3s, [ PO43-]=4s
Ksp=(3s)3(4s)4=6912 s7
∴ s= ( Ksp6912 )1/7
Answer: (3)