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Equilibrium

JEE Main 2026 (Online) 8th April Evening ShiftNumericalMedium📈 Topic in 15% papers+4
Ques. 1JEE Main 2026, 8 April (Evening Shift)

Solid carbon, CaO and CaCO3 are mixed and allowed to attain equilibrium at T K. CaCO3(s) CaO(s) + CO2(g) Kp1 = 0.08 atm C(s) + CO2(g) 2CO(g) Kp2 = 2 atm The partial pressure of CO is 10-1 atm

Answer

4

Solution

Both equilibria exist together in the same vessel, with CO2 common to both.

From (1), Kp1 = pCO2 (solids do not appear), so pCO2 = 0.08 atm.

From (2), Kp2 = pCO2pCO2, so

pCO2 = 2 0.08 = 0.16

pCO = 0.4 atm = 4 10-1 atm

Answer: 4

Keep practising — Equilibrium

Ques. 2JEE Main 2026, 6 April (Morning Shift)

One mole each of He and A(g) are taken in a 10 L closed flask and heated to 400 K to establish the following equilibrium. A(g) B(g) Kc for this reaction at 400 K is 4.0. The partial pressures (in atm) of He and B(g) are respectively (at equilibrium) (Assume He, A(g) and B(g) behave as ideal gases) (Given : R = 0.082 L atm K-1 mol-1)

  1. 3.28, 2.624
  2. 2.624, 3.28
  3. 3.28, 0.656
  4. 0.656, 6.56
Ques. 3JEE Main 2026, 6 April (Evening Shift)

Given is a concentrated solution of a weak electrolyte AxBy of concentration 'c' and dissociation constant 'K'. The degree of dissociation is given by :

  1. [K cx+y-1xxyy ]x+y
  2. ( Kcx+y-1xxyy ) 1x+y
  3. ( cx+y-1xxyyK )x+y
  4. ( cx+y-1xxyyK ) 1x+y
Ques. 4JEE Main 2026, 6 April (Evening Shift)

In a closed flask at 600 K, one mole of X2Y4(g) attains equilibrium as given below : X2Y4(g) 2XY2(g) At equilibrium, 75% X2Y4(g) was dissociated and the total pressure is 1 atm. The magnitude of rG (in kJ mol-1) at this temperature is . (Nearest Integer) (Given : R = 8.3 J mol-1 K-1; ln 10 = 2.3, log 2 = 0.3, log 3 = 0.48, log 5 = 0.69, log 7 = 0.84)

Ques. 5JEE Main 2026, 5 April (Morning Shift)

M3A2 is a sparingly soluble salt of molar mass y g mol-1 and solubility x g L-1. The ratio of the molar concentration of the anion ( A3-) to the solubility product of the salt is

  1. 154 y4x4
  2. y5108x4
  3. 108 x5y5
  4. 1108 y4x4
Ques. 6JEE Main 2026, 5 April (Morning Shift)

Arrange the following resultant mixtures in increasing order of their pH values Choose the correct answer from the options given below :

  1. B < C < A
  2. C < A < B
  3. C < B < A
  4. A < C < B
Ques. 7JEE Main 2026, 5 April (Morning Shift)

The values of pressure equilibrium constant recorded at different temperatures for the following equilibrium reaction have been given below A(g) B(g) + C(g) array|c|c| 1T ( K-1) & 10 Kp \ 0.05 & 3.5 \ 0.06 & 2.5 \ 0.07 & 1.5 \ array The magnitude of H R calculated from the above data is . (Nearest integer)

Ques. 8JEE Main 2026, 5 April (Evening Shift)

The reaction A(g) B(g) + C(g) was initiated with the amount 'a' of A(g). At equilibrium it is found that the amount of A(g) remaining is (a − x) at a total pressure of p. The equilibrium constant Kp of the reaction can be calculated from the expression :

  1. x2a2 + x2 p
  2. x2a2 - x2 p
  3. a + x2x2 p
  4. a2 - x2x2 p
Ques. 9JEE Main 2026, 4 April (Morning Shift)

At T(K), the equilibrium constant of A2(g) + B2(g) C(g) is 2.7 10-5. What is the equilibrium constant for 13A2(g) + 13B2(g) 13C(g) at the same temperature?

  1. (2.7 10-5)3
  2. 6 10-2
  3. 2.7 10-5
  4. 3 10-2
Ques. 10JEE Main 2026, 4 April (Morning Shift)

The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OH solution with 250 mL of 0.1 M NH4Cl solution is 10-2. (Nearest integer) Given: pKb(NH4OH) = 4.74 2 = 0.30 3 = 0.48 5 = 0.70

Ques. 11JEE Main 2026, 4 April (Evening Shift)

20 mL of a solution of acetic acid required 28.4 mL of 0.1 M NaOH for its neutralization. A solution (X) was prepared by mixing 20 mL of the above acetic acid and 14.2 mL of 0.1 M NaOH solution. What is the pH of the solution (X)? (pKa value of acetic acid is 4.75).

  1. 7.0
  2. 4.75
  3. 3.5
  4. 4.82

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