The pH of a solution obtained by mixing 5 mL of 0.1 M NH4OH solution with 250 mL of 0.1 M NH4Cl solution is 10-2. (Nearest integer) Given: pKb(NH4OH) = 4.74 2 = 0.30 3 = 0.48 5 = 0.70
Answer
756
Solution
NH4OH + NH4Cl is a basic buffer, and since both are in the same total volume the mole ratio can be used.
mmol of NH4OH = 5 × 0.1 = 0.5 and mmol of NH4Cl = 250 × 0.1 = 25, so
pOH = pKb + [salt][base] = 4.74 + 250.5 = 4.74 + 50
where 50 = 100 - 2 = 2 - 0.30 = 1.70
pOH = 4.74 + 1.70 = 6.44
pH = 14 − 6.44 = 7.56 = 756 × 10-2
Answer: 756