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Amines

JEE Main 2026 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 46% papers+4−1
Ques. 1JEE Main 2026, 24 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are false
  2. Statement I is false but Statement II is true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are true

Answer

(2) Statement I is false but Statement II is true

Solution

Statement I: An isocyanide on acidic hydrolysis gives a primary amine and methanoic acid, not a carboxylic acid:

R-NC + 2H2O H R-NH2 + HCOOH

so Statement I is false.

Statement II: The sequence is

R-CN H3O R-COOH SOCl2 R-COCl

R-COCl NH3 R-CONH2 (x)

R-CONH2 NaOCl/NaOH R-NH2 (Hofmann degradation)

R-NH2 + CHCl3 + 3KOH R-NC + 3KCl + 3H2O (carbylamine reaction)

Every step works, so Statement II is true.

Answer: (2)

Keep practising — Amines

Ques. 2JEE Main 2026, 23 January (Morning Shift)

Consider the following sequence of reactions. [figure] Assuming that the reaction proceeds to completion, then 137 mg of 4-nitrotoluene will produce mg of B. (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16, Br : 80)

  1. 208
  2. 228
  3. 146
  4. 301
Ques. 3JEE Main 2026, 23 January (Morning Shift)

Compound 'P' undergoes the following sequence of reactions : [figure] 'P' is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2026, 23 January (Evening Shift)

Given below are two statements : In the light of the above statements, choose the correct answer from the options given below

  1. Both Statement I and Statement II are true
  2. Statement I is false but Statement II is true
  3. Statement I is true but Statement II is false
  4. Both Statement I and Statement II are false
Ques. 5JEE Main 2026, 23 January (Evening Shift)

A student has been given a compound 'x' of molecular formula C6H7N. 'x' is sparingly soluble in water. However, on addition of dilute mineral acid, 'x' becomes soluble in water. 'x' when treated with CHCl3 and KOH(alc), 'y' is produced. 'y' has a specific unpleasant smell. On treatment with benzenesulphonyl chloride, 'x' gives a compound 'z' which is soluble in alkali. The number of different "H" atoms present in 'z' is :

  1. 8
  2. 4
  3. 5
  4. 7
Ques. 6JEE Main 2026, 22 January (Morning Shift)

'A' is a neutral organic compound (M.F. : C8H9ON). On treatment with aqueous Br2/HO , 'A' forms a compound 'B' which is soluble in dilute acid. 'B' on treatment with aqueous NaNO2/HCl (0-5 C) produces a compound 'C' which on treatment with CuCN/NaCN produces 'D'. Hydrolysis of 'D' produces 'E' which is also obtainable from the hydrolysis of 'A'. 'E' on treatment with acidified KMnO4 produces 'F'. 'F' contains two different types of hydrogen atoms. The structure of 'A' is

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 7JEE Main 2026, 22 January (Evening Shift)

[figure] The final product [B] is :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 8JEE Main 2026, 22 January (Evening Shift)

The mass of benzanilide obtained from the benzoylation reaction of 5.8 g of aniline, if yield of product is 82\%, is g (nearest integer). (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16)

Ques. 9JEE Main 2026, 21 January (Morning Shift)

An organic compound (P) on treatment with aqueous ammonia under hot condition forms compound (Q) which on heating with Br2 and KOH forms compound (R) having molecular formula C6H7N. Names of P, Q and R respectively are.

  1. Toluic acid, methylbenzamide, 2-methylaniline
  2. Benzoic acid, benzamide, aniline
  3. Benzoic acid, 4-methylbenzamide, 4-methylaniline
  4. Phenylethanoic acid, phenylethanamide, benzamine
Ques. 10JEE Main 2026, 21 January (Morning Shift)

A hydrocarbon 'P' (C4H8) on reaction with HCl gives an optically active compound 'Q' (C4H9Cl) which on reaction with one mole of ammonia gives compound 'R' ( C4H11N). 'R' on diazotization followed by hydrolysis gives 'S'. Identify P, Q, R and S.

  1. P=CH3-CH=CH-CH3, Q=CH3-CH2-CH2-CH2-Cl, R=CH3-CH2-CH2- NH2 |CH2, S=CH3-CH2- OH |CH2 |CH2
  2. P=CH3-CH=CH-CH3, Q=CH3-CH2- Cl |CH-CH3, R=CH3-CH2- NH2 |CH-CH3, S=CH3-CH2- OH |CH-CH3
  3. P = [figure] , Q = [figure] , R = [figure] , S = [figure]
  4. P=CH3-CH2-CH=CH2, Q=CH3-CH2-CH2- Cl |CH2, R=CH3-CH2-CH2- CH3 |NH, S=CH3-CH2- OH | CH3 |CH
Ques. 11JEE Main 2026, 21 January (Morning Shift)

Consider the following reaction sequence [figure] The percentage of nitrogen in product 'T' formed is %. (Nearest integer) (Given molar mass in g mol-1 H : 1, C : 12, N : 14, O : 16)

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