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System of Particles and Rotational Motion

JEE Main 2025 (Online) 28th January Morning ShiftMCQEasy📈 Topic in 12% papers+4−1
Ques. 1JEE Main 2025, 28 January (Morning Shift)

The center of mass of a thin rectangular plate (fig - x) with sides of length a and b, whose mass per unit area ( ) varies as = 0 xab (where 0 is a constant), would be . [figure]

  1. ( 23a, 23b )
  2. ( 23a, b2 )
  3. ( 13a, b2 )
  4. ( a2, b2 )

Answer

(2) ( 23a, b2 )

Solution

Take a strip of width dx at distance x from the y-axis:

dm = b dx = 0 xab b dx = 0ax dx

M = 0a 0ax dx = 0 a2

xcm = 1M 0a x dm = 0a a33 0 a2 = 2a3

does not depend on y mass is uniform along y ycm = b2

Centre of mass = ( 23a, b2 )

Answer: (2)

Keep practising — System of Particles and Rotational Motion

Ques. 2JEE Main 2025, 28 January (Morning Shift)

Two iron solid discs of negligible thickness have radii R1 and R2 and moment of inertia I1 and I2, respectively. For R2 = 2R1, the ratio of I1 and I2 would be 1/x, where x = .

Ques. 3JEE Main 2025, 28 January (Morning Shift)

The moment of inertia of a solid disc rotating along its diameter is 2.5 times higher than the moment of inertia of a ring rotating in similar way. The moment of inertia of a solid sphere which has same radius as the disc and rotating in similar way, is n times higher than the moment of inertia of the given ring. Here, n = . Consider all the bodies have equal masses.

Ques. 4JEE Main 2025, 28 January (Evening Shift)

A uniform rod of mass 250 g having length 100 cm is balanced on a sharp edge at 40 cm mark. A mass of 400 g is suspended at 10 cm mark. To maintain the balance of the rod, the mass to be suspended at 90 cm mark, is

  1. 290 g
  2. 200 g
  3. 190 g
  4. 300 g
Ques. 5JEE Main 2025, 24 January (Morning Shift)

An object of mass 'm' is projected from origin in a vertical xy plane at an angle 45 with the x-axis with an initial velocity v0. The magnitude and direction of the angular momentum of the object with respect to origin, when it reaches at the maximum height, will be [ g is acceleration due to gravity]

  1. mv032 2 g along negative z-axis
  2. mv032 2 g along positive z-axis
  3. mv034 2 g along positive z-axis
  4. mv034 2 g along negative z-axis
Ques. 6JEE Main 2025, 24 January (Morning Shift)

A uniform solid cylinder of mass 'm' and radius 'r' rolls along an inclined rough plane of inclination 45 . If it starts to roll from rest from the top of the plane then the linear acceleration of the cylinder's axis will be

  1. 2 g
  2. 1 2 g
  3. 13 2 g
  4. 2 g3
Ques. 7JEE Main 2025, 24 January (Evening Shift)

A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be t1 and t2, respectively, then

  1. t1 < t2
  2. t1 = 2t2
  3. t1 > t2
  4. t1 = t2
Ques. 8JEE Main 2025, 24 January (Evening Shift)

A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre of mass of the sphere and rotational kinetic energy is :

  1. 34
  2. 43
  3. 52
  4. 25
Ques. 9JEE Main 2025, 23 January (Morning Shift)

A solid sphere of mass ' m ' and radius ' r ' is allowed to roll without slipping from the highest point of an inclined plane of length ' L ' and makes an angle 30 with the horizontal. The speed of the particle at the bottom of the plane is v1. If the angle of inclination is increased to 45 while keeping L constant. Then the new speed of the sphere at the bottom of the plane is v2. The ratio v12:v22 is

  1. 1:3
  2. 1:2
  3. 1: 2
  4. 1: 3
Ques. 10JEE Main 2025, 23 January (Morning Shift)

Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be

  1. 1.5 cm
  2. 2.0 cm
  3. 0.5 cm
  4. 1.0 cm
Ques. 11JEE Main 2025, 23 January (Evening Shift)

A circular disk of radius R meter and mass M kg is rotating around the axis perpendicular to the disk. An external torque is applied to the disk such that (t)=5t2-8t, where (t) is the angular position of the rotating disc as a function of time t. How much power is delivered by the applied torque, when t=2 s ?

  1. 60 MR2
  2. 72 MR2
  3. 8 MR2
  4. 108 MR2

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