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System of Particles and Rotational Motion

JEE Main 2025 (Online) 24th January Evening ShiftMCQEasy📈 Topic in 28% papers+4−1
Ques. 1JEE Main 2025, 24 January (Evening Shift)

A solid sphere and a hollow sphere of the same mass and of same radius are rolled on an inclined plane. Let the time taken to reach the bottom by the solid sphere and the hollow sphere be t1 and t2, respectively, then

  1. t1 < t2
  2. t1 = 2t2
  3. t1 > t2
  4. t1 = t2

Answer

(1) t1 < t2

Solution

Rolling down an incline: a= g 1+I/MR2

[figure]

Solid sphere ( IMR2= 25 ): a1= 57g

Hollow sphere ( 23 ): a2= 35g

s= 12at2 t 1 a; a1>a2

t1<t2

Answer: (1)

Keep practising — System of Particles and Rotational Motion

Ques. 2JEE Main 2025, 24 January (Evening Shift)

A solid sphere is rolling without slipping on a horizontal plane. The ratio of the linear kinetic energy of the centre of mass of the sphere and rotational kinetic energy is :

  1. 34
  2. 43
  3. 52
  4. 25
Ques. 3JEE Main 2025, 23 January (Morning Shift)

A solid sphere of mass ' m ' and radius ' r ' is allowed to roll without slipping from the highest point of an inclined plane of length ' L ' and makes an angle 30 with the horizontal. The speed of the particle at the bottom of the plane is v1. If the angle of inclination is increased to 45 while keeping L constant. Then the new speed of the sphere at the bottom of the plane is v2. The ratio v12:v22 is

  1. 1:3
  2. 1:2
  3. 1: 2
  4. 1: 3
Ques. 4JEE Main 2025, 23 January (Morning Shift)

Consider a circular disc of radius 20 cm with centre located at the origin. A circular hole of radius 5 cm is cut from this disc in such a way that the edge of the hole touches the edge of the disc. The distance of centre of mass of residual or remaining disc from the origin will be

  1. 1.5 cm
  2. 2.0 cm
  3. 0.5 cm
  4. 1.0 cm
Ques. 5JEE Main 2025, 23 January (Evening Shift)

A circular disk of radius R meter and mass M kg is rotating around the axis perpendicular to the disk. An external torque is applied to the disk such that (t)=5t2-8t, where (t) is the angular position of the rotating disc as a function of time t. How much power is delivered by the applied torque, when t=2 s ?

  1. 60 MR2
  2. 72 MR2
  3. 8 MR2
  4. 108 MR2
Ques. 6JEE Main 2025, 22 January (Morning Shift)

A uniform circular disc of radius ' R ' and mass ' M ' is rotating about an axis perpendicular to its plane and passing through its centre. A small circular part of radius R/2 is removed from the original disc as shown in the figure. Find the moment of inertia of the remaining part of the original disc about the axis as given above. [figure]

  1. 1732MR2
  2. 1332MR2
  3. 932MR2
  4. 732MR2
Ques. 7JEE Main 2025, 22 January (Morning Shift)

The position vectors of two 1 kg particles, (A) and (B), are given by rA= ( 1t2 i+ 2t j+ 3t k )m and rB= ( 1t i+ 2t2 j+ 3t k )m, respectively; ( 1=1 m/s2, 2=3n m/s, 3=2 m/s, 1=2 m/s, 2=-1 m/s2, 3=4p m/s), where t is time, n and p are constants. At t=1 s, | VA |= | VB | and velocities VA and VB of the particles are orthogonal to each other. At t=1 s, the magnitude of angular momentum of particle (A) with respect to the position of particle (B) is L kg m2 s-1. The value of L is .

Ques. 8JEE Main 2025, 22 January (Evening Shift)

The torque due to the force (2 i+ j+2 k ) about the origin, acting on a particle whose position vector is ( i+ j+ k ), would be

  1. j+ k
  2. i- k
  3. i- j+ k
  4. i+ k
Ques. 9JEE Main 2024, 9 April (Morning Shift)

A heavy iron bar, of weight W is having its one end on the ground and the other on the shoulder of a person. The bar makes an angle with the horizontal. The weight experienced by the person is :

  1. W
  2. W
  3. W2
  4. W
Ques. 10JEE Main 2024, 9 April (Morning Shift)

A string is wrapped around the rim of a wheel of moment of inertia 0.40 kgm2 and radius 10 cm. The wheel is free to rotate about its axis. Initially the wheel is at rest. The string is now pulled by a force of 40 N. The angular velocity of the wheel after 10 s is x rad/s, where x is .

Ques. 11JEE Main 2024, 9 April (Evening Shift)

A circular disc reaches from top to bottom of an inclined plane of length l. When it slips down the plane, it takes t s. When it rolls down the plane then it takes ( 2 )1/2t s, where is .

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