A circular disk of radius R meter and mass M kg is rotating around the axis perpendicular to the disk. An external torque is applied to the disk such that (t)=5t2-8t, where (t) is the angular position of the rotating disc as a function of time t. How much power is delivered by the applied torque, when t=2 s ?
- 60 MR2
- 72 MR2
- 8 MR2
- 108 MR2
Answer
(1) 60 MR2
Solution
= d dt=10t-8, =10 rad s-2; at t=2 s: =12 rad s-1
=I = 12MR2 10=5MR2
P= =5MR2 12=60 MR2
Answer: (1)