Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Dual Nature of Radiation and Matter

JEE Main 2025 (Online) 4th April Morning ShiftMCQMedium📈 Topic in 10% papers+4−1
Ques. 1JEE Main 2025, 4 April (Morning Shift)

A small mirror of mass m is suspended by a massless thread of length l. Then the small angle through which the thread will be deflected when a short pulse of laser of energy E falls normal on the mirror (c = speed of light in vacuum and g = acceleration due to gravity)

  1. = Emc gl
  2. = E2mc gl
  3. = 3E4mc gl
  4. = 2Emc gl

Answer

(4) = 2Emc gl

Solution

Momentum of the light pulse: p = Ec

The mirror reflects the pulse back, so the momentum given to the mirror: p = Ec - (- Ec ) = 2Ec

Speed of the mirror just after the pulse: v = 2Emc

Energy conservation as it swings up: 12mv2 = mgl(1 - )

For small : 1 - 22 v2 = gl 2 v = gl

= v gl = 2Emc gl

Answer: (4)

Keep practising — Dual Nature of Radiation and Matter

Ques. 2JEE Main 2025, 4 April (Morning Shift)

Given below are two statements: one is labelled as Assertion A and the other is labelled as Reason R In the light of the above statements, choose the correct answer from the options given below

  1. Both A and R are true and R is the correct explanation of A
  2. A is false but R is true
  3. Both A and R are true but R is NOT the correct explanation of A
  4. A is true but R is false
Ques. 3JEE Main 2025, 3 April (Morning Shift)

The work function of a metal is 3 eV. The color of the visible light that is required to cause emission of photoelectrons is

  1. Red
  2. Green
  3. Blue
  4. Yellow
Ques. 4JEE Main 2025, 29 January (Morning Shift)

If and K are de Broglie wavelength and kinetic energy, respectively, of a particle with constant mass, the correct graphical representation for the particle will be :

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 5JEE Main 2025, 29 January (Morning Shift)

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. Both (A) and (R) are true and (R) is the correct explanation of (A).
  2. Both (A) and (R) are true but (R) is not the correct explanation of (A).
  3. (A) is false but (R) is true
  4. (A) is true but (R) is false
Ques. 6JEE Main 2025, 29 January (Evening Shift)

In an experiment with photoelectric effect, the stopping potential,

  1. is ( 1e ) times the maximum kinetic energy of the emitted photoelectrons
  2. increases with increase in the intensity of the incident light
  3. decreases with increase in the intensity of the incident light
  4. increases with increase in the wavelength of the incident light
Ques. 7JEE Main 2025, 28 January (Morning Shift)

A proton of mass 'mp' has same energy 'E' as that of a photon of wavelength ' '. If the proton is moving at non-relativistic speed, then ratio of its de Broglie wavelength to the wavelength of photon is

  1. 1c Emp
  2. 1c 2Emp
  3. 12c Emp
  4. 1c E2mp
Ques. 8JEE Main 2025, 28 January (Evening Shift)

Which of the following phenomena cannot be explained by wave theory of light?

  1. Refraction of light
  2. Reflection of light
  3. Diffraction of light
  4. Compton effect
Ques. 9JEE Main 2025, 24 January (Morning Shift)

An electron of mass 'm' with an initial velocity v=v0 i (v0>0) enters an electric field E=-Eo k. If the initial de Broglie wavelength is 0, the value after time t would be

  1. o 1- e2Eo2t2m2vo2
  2. 0
  3. o 1+ e2Eo2t2m2vo2
  4. o 1+ e2Eo2t2m2vo2
Ques. 10JEE Main 2025, 24 January (Evening Shift)

In photoelectric effect, the stopping potential (V0) v/s frequency ( ) curve is plotted. ( h is the Planck's constant and 0 is work function of metal ) Choose the correct answer from the options given below :

  1. (A), (C) and (E) only
  2. (C) and (D) only
  3. (A), (B) and (C) only
  4. (D) and (E) only
Ques. 11JEE Main 2025, 24 January (Evening Shift)

The ratio of the power of a light source S1 to that of the light source S2 is 2. S1 is emitting 2 1015 photons per second at 600 nm. If the wavelength of the source S2 is 300 nm, then the number of photons per second emitted by S2 is 1014.

All Dual Nature of Radiation and Matter PYQs →

PDFDownload Dual Nature of Radiation and Matter PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters