In an experiment with photoelectric effect, the stopping potential,
- is ( 1e ) times the maximum kinetic energy of the emitted photoelectrons
- increases with increase in the intensity of the incident light
- decreases with increase in the intensity of the incident light
- increases with increase in the wavelength of the incident light
Answer
(1) is ( 1e ) times the maximum kinetic energy of the emitted photoelectrons
Solution
eV0=K =h - 0 ⇒ V0= 1eK
[figure]
Intensity changes only the number of photoelectrons ⇒ V0 independent of intensity
V0= hce - 0e ⇒ V0 falls as rises
∴ only (1) is correct
Answer: (1)