Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Alternating Current

JEE Main 2025 (Online) 7th April Morning ShiftNumericalHard📈 Topic in 3% papers+4
Ques. 1JEE Main 2025, 7 April (Morning Shift)

For ac circuit shown in figure, R = 100 k and C = 100 pF and the phase difference between Vin and (VB - VA) is 90 . The input signal frequency is 10x rad/sec, where 'x' is . [figure]

Answer

5

Solution

Let Vin = V and a = RC. Each branch is an R–C divider across the source.

In the left branch (R on top, C below), VA = V 1/(j C)R + 1/(j C) = V1 + ja, and in the right branch (C on top, R below), VB = V RR + 1/(j C) = jaV1 + ja, so

VB - VA = V ja - 11 + ja

The phase of (VB - VA) relative to Vin is therefore

= (180 - -1a) - -1a = 180 - 2 -1a

For = 90 , -1a = 45 , i.e. RC = 1, so

= 1RC = 1(100 103)(100 10-12) = 105 rad/s

x = 5

Answer: 5

Keep practising — Alternating Current

Ques. 2JEE Main 2025, 7 April (Evening Shift)

An inductor of reactance 100 , a capacitor of reactance 50 , and a resistor of resistance 50 are connected in series with an AC source of 10 V, 50 Hz. Average power dissipated by the circuit is W.

Ques. 3JEE Main 2025, 4 April (Morning Shift)

An alternating current is represented by the equation, i = 100 2 (100 t) ampere. The RMS value of current and the frequency of the given alternating current are

  1. 100 2 A, 100 Hz
  2. 50 2 A, 50 Hz
  3. 100 2 A, 100 Hz
  4. 100 A, 50 Hz
Ques. 4JEE Main 2025, 4 April (Evening Shift)

An inductor of self inductance 1 H is connected in series with a resistor of 100 ohm and an ac supply of 100 volt, 50 Hz. Maximum current flowing in the circuit is A.

Ques. 5JEE Main 2025, 3 April (Evening Shift)

An electric bulb rated as 100 W - 220 V is connected to an ac source of rms voltage 220 V. The peak value of current through the bulb is:

  1. 0.32 A
  2. 0.64 A
  3. 0.45 A
  4. 2.2 A
Ques. 6JEE Main 2025, 29 January (Morning Shift)

Given below are two statements: one is labelled as Assertion (A) and the other is labelled as Reason (R). In the light of the above statements, choose the most appropriate answer from the options given below :

  1. (A) is true but (R) is false
  2. Both (A) and (R) are true and (R) is the correct explanation of (A).
  3. Both (A) and (R) are true but (R) is not the correct explanation of (A)
  4. (A) is false but (R) is true
Ques. 7JEE Main 2025, 24 January (Morning Shift)

An alternating current is given by I=IA t+IB t. The r.m.s current will be

  1. IA2+IB22
  2. IA2+IB22
  3. |IA+IB| 2
  4. IA2+IB2
Ques. 8JEE Main 2025, 23 January (Evening Shift)

In a series LCR circuit, a resistor of 300 , a capacitor of 25 nF and an inductor of 100 mH are used. For maximum current in the circuit, the angular frequency of the ac source is 104 radians s-1

Ques. 9JEE Main 2025, 22 January (Evening Shift)

A series LCR circuit is connected to an alternating source of emf E. The current amplitude at resonant frequency is I0. If the value of resistance R becomes twice of its initial value then amplitude of current at resonance will be

  1. I02
  2. I0 2
  3. 2I0
  4. I0
Ques. 10JEE Main 2024, 9 April (Morning Shift)

A bulb and a capacitor are connected in series across an ac supply. A dielectric is then placed between the plates of the capacitor. The glow of the bulb :

  1. becomes zero
  2. remains same
  3. increases
  4. decreases
Ques. 11JEE Main 2024, 9 April (Morning Shift)

When a coil is connected across a 20 V dc supply, it draws a current of 5 A. When it is connected across 20 V, 50 Hz ac supply, it draws a current of 4 A. The self inductance of the coil is mH. (Take = 3)

All Alternating Current PYQs →

PDFDownload Alternating Current PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Physics chapters