An alternating current is given by I=IA t+IB t. The r.m.s current will be
- IA2+IB22
- IA2+IB22
- |IA+IB| 2
- IA2+IB2
Answer
(2) IA2+IB22
Solution
I=IA t+IB t=I0 ( t+ ):
[figure]
I0= IA2+IB2 and Irms= I0 2= IA2+IB22
Answer: (2)
An alternating current is given by I=IA t+IB t. The r.m.s current will be
(2) IA2+IB22
I=IA t+IB t=I0 ( t+ ):
[figure]
I0= IA2+IB2 and Irms= I0 2= IA2+IB22
Answer: (2)
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