A capacitor of reactance 4 3 and a resistor of resistance 4 are connected in series with an ac source of peak value 8 2 V. The power dissipation in the circuit is W.
Answer
4
Solution
Z = R2 + XC2 = 16 + 48 = 8
Vrms = 8 2 2 = 8 V, so Irms = 88 = 1 A
Since only the resistor dissipates power,
P = Irms2R = 12 4 = 4 W
Answer: 4