A hypothetical electromagnetic wave is shown below. [figure] The frequency of the wave is x 1019 Hz. x = (nearest integer)
Answer
5
Solution
[figure]
The marked distance runs from a crest to the next zero, i.e. one quarter of a wave:
4 = 1.5 pm, so λ = 6 pm = 6 10-12 m
ν = c = 3 1086 10-12 = 5 1019 Hz
∴ x = 5
Answer: 5