For hydrogen atom, energy of an electron in first excited state is -3.4 eV. K.E. of the same electron of hydrogen atom is x eV. Value of x is 10-1 eV. (Nearest integer)
Answer
34
Solution
Bohr model: K.E. = kZe22r and E = - kZe22r
∵ K.E. = -E for every orbit
⇒ K.E. = -(-3.4) = 3.4 eV = 34 10-1 eV
Answer: 34