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Structure of Atom

JEE Main 2024 (Online) 8th April Evening ShiftNumericalEasy📈 Topic in 3% papers+4
Ques. 1JEE Main 2024, 8 April (Evening Shift)

Wavenumber for a radiation having 5800 Å wavelength is x 10 cm-1. The value of x is . (Integer answer)

Answer

1724

Solution

= 1 with λ = 5800 Å = 5800 10-8 cm

= 15800 10-8 = 17241 cm-1

= 1724.1 10 cm-1, so x = 1724.

Answer: 1724

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Ques. 2JEE Main 2024, 6 April (Morning Shift)

Frequency of the de-Broglie wave of electron in Bohr's first orbit of hydrogen atom is 1013 Hz (nearest integer). [Given : RH (Rydberg constant) = 2.18 10-18 J, h (Planck's constant) = 6.6 10-34 J. s.]

Ques. 3JEE Main 2024, 6 April (Evening Shift)

For hydrogen atom, energy of an electron in first excited state is -3.4 eV. K.E. of the same electron of hydrogen atom is x eV. Value of x is 10-1 eV. (Nearest integer)

Ques. 4JEE Main 2024, 5 April (Morning Shift)

The value of Rydberg constant (RH) is 2.18 10-18 J. The velocity of electron having mass 9.1 10-31 kg in Bohr's first orbit of hydrogen atom = 105 ms-1 (nearest integer).

Ques. 5JEE Main 2024, 5 April (Evening Shift)

In an atom, total number of electrons having quantum numbers n = 4, |ml| = 1 and ms = - 12 is .

Ques. 6JEE Main 2024, 4 April (Morning Shift)

The de-Broglie's wavelength of an electron in the 4th orbit is 0. (a0 = Bohr's radius)

Ques. 7JEE Main 2024, 4 April (Evening Shift)

The maximum number of orbitals which can be identified with n = 4 and ml = 0 is .

Ques. 8JEE Main 2024, 1 February (Morning Shift)

According to the wave-particle duality of matter by de-Broglie, which of the following graph plot presents most appropriate relationship between wavelength of electron ( ) and momentum of electron (p)?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 9JEE Main 2024, 1 February (Evening Shift)

The number of radial node/s for 3p orbital is :

  1. 3
  2. 2
  3. 1
  4. 4
Ques. 10JEE Main 2024, 31 January (Morning Shift)

The ionization energy of sodium in kJ mol-1, if electromagnetic radiation of wavelength 242 nm is just sufficient to ionize sodium atom is .

Ques. 11JEE Main 2024, 31 January (Evening Shift)

The four quantum numbers for the electron in the outermost orbital of potassium (atomic no. 19) are

  1. n = 3, l = 0, m = 1, s = + 12
  2. n = 4, l = 0, m = 0, s = + 12
  3. n = 2, l = 0, m = 0, s = + 12
  4. n = 4, l = 2, m = -1, s = + 12

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