Mass of magnesium required to produce 220 mL of hydrogen gas at STP on reaction with excess of dil. HCl is Given: Molar mass of Mg is 24 g mol-1.
(4) 236 mg
Mg + 2HCl MgCl2 + H2
1 mol Mg gives 1 mol H2
Moles of H2 = 220 mL22400 mL mol-1
= 9.82 10-3 mol
Moles of Mg = 9.82 10-3 mol
Mass of Mg = 9.82 10-3 24
= 0.2357 g = 235.7 mg 236 mg
Answer: (4)
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