When a coil is placed in a time dependent magnetic field the power dissipated in it is P. The number of turns, area of the coil and radius of the coil wire are N, A and r respectively. For a second coil number of turns, area of the coil and radius of the coil wire are 2N, 2A and 3r respectively. When the first coil is replaced with second coil the power dissipated in it is 2 P. The value of is .
- 36
- 128 2
- 16
- 64
Answer
(1) 36
Solution
The induced emf is = NA dBdt, so NA.
For coil radius a, A = a2, so a A; the wire length is N(2 a) N A and its cross-section is r2, hence
Rcoil = N(2 a) r2 N Ar2
P = 2Rcoil N2A2r2N A = NA3/2r2
P'P = (2)(2)3/2(3)2 = 2 2 2 9 = 36 2
P' = 36 2 P = 2 P, so = 36
Answer: (1)