Consider an A.P.: a1, a2, , an; a1 > 0. If a2 - a1 = -34, an = 14a1, and i=1n ai = 5252, then i=117 ai is equal to
- 238
- 136
- 476
- 952
Answer
(1) 238
Solution
The common difference is d = a2 - a1 = - 34, and an = a1 + (n - 1)d = 14a1, so
34a1 = 34(n - 1) a1 = n - 1
The sum of n terms is i=1n ai = n2(a1 + an) = n2 54a1 = 5n(n - 1)8, hence
5n(n - 1)8 = 5252
n(n - 1) = 420 = 21 20
So n = 21 and a1 = 20, which gives
i=117 ai = 172 [2(20) + 16 (- 34 ) ] = 172(40 - 12)
i=117 ai = 17 14 = 238
Answer: (1)