Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Sequences and Series

JEE Main 2026 (Online) 24th January Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2026, 24 January (Evening Shift)

( 13 + 47 ) + ( 132 + 13 47 + 4272 ) + ( 133 + 132 47 + 13 4272 + 4373 ) + up to infinite terms, is equal to

  1. 74
  2. 43
  3. 65
  4. 52

Answer

(4) 52

Solution

The r-th bracket = m + n = r ( 13 )m ( 47 )n (m, n 0)

So the series contains every product ( 13 )m ( 47 )n exactly once, except m = n = 0 (the term 1).

S = ( m=0 13m ) ( n=0 ( 47 )n ) - 1

= 11 - 13 11 - 47 - 1

= 32 73 - 1

= 72 - 1 = 52

Answer: (4)

Keep practising — Sequences and Series

Ques. 2JEE Main 2026, 23 January (Evening Shift)

Let k=1n ak = n2 + n. If a10 = 59 and a6 = 7a1, then + is equal to :

  1. 3
  2. 5
  3. 7
  4. 12
Ques. 3JEE Main 2026, 22 January (Morning Shift)

If the sum of the first four terms of an A.P. is 6 and the sum of its first six terms is 4, then the sum of its first twelve terms is

  1. -26
  2. -20
  3. -24
  4. -22
Ques. 4JEE Main 2026, 22 January (Evening Shift)

Suppose a, b, c are in A.P. and a2, 2b2, c2 are in G.P. If a < b < c and a + b + c = 1, then 9(a2 + b2 + c2) is equal to .

Ques. 5JEE Main 2026, 21 January (Morning Shift)

Let a1, a2, a3, be a G.P. of increasing positive terms such that a2 a3 a4 = 64 and a1 + a3 + a5 = 8137. Then a3 + a5 + a7 is equal to :

  1. 3256
  2. 3252
  3. 3248
  4. 3244
Ques. 6JEE Main 2026, 21 January (Morning Shift)

Let a1 = 1 and for n 1, an+1 = 12an + n2 - 2n - 1n2(n + 1)2. Then | n=1 (an - 2n2 ) | is equal to .

Ques. 7JEE Main 2026, 21 January (Evening Shift)

The positive integer n, for which the solutions of the equation x(x + 2) + (x + 2)(x + 4) + + (x + 2n - 2)(x + 2n) = 8n3 are two consecutive even integers, is :

  1. 3
  2. 6
  3. 9
  4. 12
Ques. 8JEE Main 2026, 21 January (Evening Shift)

Let a1, a22, a322, , a1029 be a G.P. of common ratio 1 2. If a1 + a2 + + a10 = 62, then a1 is equal to:

  1. 2 - 1
  2. 2( 2 - 1)
  3. 2 - 2
  4. 2(2 - 2)
Ques. 9JEE Main 2025, 8 April (Evening Shift)

If 114 + 124 + 134 + = 490, 114 + 134 + 154 + = , 124 + 144 + 164 + = , then is equal to :

  1. 23
  2. 14
  3. 18
  4. 15
Ques. 10JEE Main 2025, 7 April (Morning Shift)

Let x1, x2, x3, x4 be in a geometric progression. If 2, 7, 9, 5 are subtracted respectively from x1, x2, x3, x4, then the resulting numbers are in an arithmetic progression. Then the value of 124(x1 x2 x3 x4) is:

  1. 18
  2. 216
  3. 36
  4. 72
Ques. 11JEE Main 2025, 7 April (Evening Shift)

Let an be the nth term of an A.P. If Sn = a1 + a2 + a3 + + an = 700, a6 = 7 and S7 = 7, then an is equal to :

  1. 65
  2. 56
  3. 70
  4. 64

All Sequences and Series PYQs →

PDFDownload Sequences and Series PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters