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Sequences and Series

JEE Main 2026 (Online) 24th January Morning ShiftMCQMedium📈 Topic in 37% papers+4−1
Ques. 1JEE Main 2026, 24 January (Morning Shift)

Let 729, 81, 9, 1, be a sequence and Pn denote the product of the first n terms of this sequence. If 2 n=140(Pn) 1n = 3 -13 and ( , ) = 1, then + is equal to

  1. 73
  2. 74
  3. 75
  4. 76

Answer

(1) 73

Solution

The sequence is a G.P. with first term 729 = 36 and common ratio 19 = 3-2.

ak = 36 3-2(k-1) = 38-2k

Pn = 3 k=1n(8-2k) = 38n-n(n+1) = 37n-n2

(Pn) 1n = 37-n

n=140(Pn) 1n = 36 + 35 + + 3-33 (G.P. of 40 terms, common ratio 13)

= 36 (1-3-40 )1- 13 = 37 (1-3-40 )2

2 n=140(Pn) 1n = 37 - 3-33 = 340-1333

= 40, = 33 and (40, 33) = 1

+ = 73

Answer: (1)

Keep practising — Sequences and Series

Ques. 2JEE Main 2026, 24 January (Morning Shift)

Consider an A.P.: a1, a2, , an; a1 > 0. If a2 - a1 = -34, an = 14a1, and i=1n ai = 5252, then i=117 ai is equal to

  1. 238
  2. 136
  3. 476
  4. 952
Ques. 3JEE Main 2026, 24 January (Evening Shift)

Let a1, a2, a3, a4 be an A.P. of four terms such that each term of the A.P. and its common difference l are integers. If a1 + a2 + a3 + a4 = 48 and a1a2a3a4 + l4 = 361, then the largest term of the A.P. is equal to

  1. 27
  2. 24
  3. 23
  4. 21
Ques. 4JEE Main 2026, 24 January (Evening Shift)

( 13 + 47 ) + ( 132 + 13 47 + 4272 ) + ( 133 + 132 47 + 13 4272 + 4373 ) + up to infinite terms, is equal to

  1. 74
  2. 43
  3. 65
  4. 52
Ques. 5JEE Main 2026, 23 January (Evening Shift)

Let k=1n ak = n2 + n. If a10 = 59 and a6 = 7a1, then + is equal to :

  1. 3
  2. 5
  3. 7
  4. 12
Ques. 6JEE Main 2026, 22 January (Morning Shift)

If the sum of the first four terms of an A.P. is 6 and the sum of its first six terms is 4, then the sum of its first twelve terms is

  1. -26
  2. -20
  3. -24
  4. -22
Ques. 7JEE Main 2026, 22 January (Evening Shift)

Suppose a, b, c are in A.P. and a2, 2b2, c2 are in G.P. If a < b < c and a + b + c = 1, then 9(a2 + b2 + c2) is equal to .

Ques. 8JEE Main 2026, 21 January (Morning Shift)

Let a1, a2, a3, be a G.P. of increasing positive terms such that a2 a3 a4 = 64 and a1 + a3 + a5 = 8137. Then a3 + a5 + a7 is equal to :

  1. 3256
  2. 3252
  3. 3248
  4. 3244
Ques. 9JEE Main 2026, 21 January (Morning Shift)

Let a1 = 1 and for n 1, an+1 = 12an + n2 - 2n - 1n2(n + 1)2. Then | n=1 (an - 2n2 ) | is equal to .

Ques. 10JEE Main 2026, 21 January (Evening Shift)

The positive integer n, for which the solutions of the equation x(x + 2) + (x + 2)(x + 4) + + (x + 2n - 2)(x + 2n) = 8n3 are two consecutive even integers, is :

  1. 3
  2. 6
  3. 9
  4. 12
Ques. 11JEE Main 2026, 21 January (Evening Shift)

Let a1, a22, a322, , a1029 be a G.P. of common ratio 1 2. If a1 + a2 + + a10 = 62, then a1 is equal to:

  1. 2 - 1
  2. 2( 2 - 1)
  3. 2 - 2
  4. 2(2 - 2)

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