The correct order of total number of atoms present in (A) 2 moles of cyclohexane (B) 684 g of sucrose (C) 90.8 L of dihydrogen at STP is :
- C > A > B
- C > B > A
- B > C > A
- B > A > C
Answer
(4) B > A > C
Solution
The number of atoms = moles of molecules × atoms per molecule (× NA, which is common to all).
(A) Cyclohexane, C6H12, has 6 + 12 = 18 atoms per molecule, so atoms = 2 × 18 = 36 mol of atoms.
(B) Sucrose, C12H22O11, has 45 atoms per molecule and M = 342 g mol-1, so n = 684342 = 2 mol and atoms = 2 × 45 = 90 mol of atoms.
(C) For dihydrogen, H2, the molar volume at STP (1 bar, 273.15 K) is 22.7 L, so n = 90.822.7 = 4 mol and atoms = 4 × 2 = 8 mol of atoms.
∴ B (90 NA) > A (36 NA) > C (8 NA)
Answer: (4)