[figure] An infinite wire has a circular bend of radius a, and carrying a current I as shown in the figure. The magnitude of magnetic field at the origin O of the arc is given by:
- 02 Ia [ 2+2 ]
- 04 Ia [ 3 2+1 ]
- 04 Ia [ 2+1 ]
- 04 Ia [ 3 2+2 ]
Answer
(2) 04 Ia [ 3 2+1 ]
Solution
The lower straight wire (from to the foot of the perpendicular from O, distance a) is a semi-infinite wire with O on the perpendicular through its end, so B1 = 0 I4 a, into the page.
The circular part is three-quarters of a circle (270 = 3 2) with clockwise current, so B2 = 34 0 I2a = 0 I4 a 3 2, also into the page.
O lies on the line of the upper straight wire, so d l r and B3 = 0.
All the non-zero fields are in the same direction, hence
B = B1 + B2 = 04 Ia [ 3 2+1 ]
Answer: (2)