A long straight wire of a circular cross-section with radius 'a' carries a steady current I. The current I is uniformly distributed across this cross-section. The plot of magnitude of magnetic field B with distance r from the centre of the wire is given by
- [figure]
- [figure]
- [figure]
- [figure]
Answer
(2) [figure]
Solution
Ampere's law on a circle of radius r: B 2 r= 0Ienc.
[figure]
r<a: Ienc= Ir2a2 B= 0I2 a2 r r (straight line from the origin)
r>a: Ienc=I B= 0I2 r 1r (falls)
Both agree at r=a (peak) graph (B)
Answer: (2)