A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of 2 105 m s-1. When the electric field is switched off, the proton moves along a circular path of radius 2 cm . The magnitude of electric field is x 104 N/C. The value of x is . Take the mass of the proton =1.6 10-27 kg.
Answer
2
Solution
[figure]
Undeflected: qE=qvB E=vB; E off: qvB= mv2r B= mvqr
E= mv2qr= (1.6 10-27)(2 105)2(1.6 10-19)(2 10-2)=2 104 N/C
x=2
Answer: 2