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Moving Charges and Magnetism

JEE Main 2025 (Online) 22nd January Evening ShiftNumericalMedium📈 Topic in 5% papers+4
Ques. 1JEE Main 2025, 22 January (Evening Shift)

A proton is moving undeflected in a region of crossed electric and magnetic fields at a constant speed of 2 105 m s-1. When the electric field is switched off, the proton moves along a circular path of radius 2 cm . The magnitude of electric field is x 104 N/C. The value of x is . Take the mass of the proton =1.6 10-27 kg.

Answer

2

Solution

[figure]

Undeflected: qE=qvB E=vB; E off: qvB= mv2r B= mvqr

E= mv2qr= (1.6 10-27)(2 105)2(1.6 10-19)(2 10-2)=2 104 N/C

x=2

Answer: 2

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Ques. 2JEE Main 2025, 22 January (Evening Shift)

Two long parallel wires X and Y, separated by a distance of 6 cm , carry currents of 5 A and 4A, respectively, in opposite directions as shown in the figure. Magnitude of the resultant magnetic field at point P at a distance of 4 cm from wire Y is x 10-5 T. The value of x is . Take permeability of free space as 0=4 10-7 SI units. [figure]

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