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Oscillations

JEE Main 2026 (Online) 6th April Morning ShiftMCQEasy📈 Topic in 5% papers+4−1
Ques. 1JEE Main 2026, 6 April (Morning Shift)

A particle is executing simple harmonic motion. Its amplitude is A and time period is 5 sec. The time required by it to move from x=A to x= A 2 is sec.

  1. 1/4
  2. 5/4
  3. 5/8
  4. 3/8

Answer

(3) 5/8

Solution

Starting from the extreme position x=A:

x=A t

A 2=A t ⇒ t= 4

⇒ t= /42 /T= T8

∴ t= 58 s

Answer: (3)

Keep practising — Oscillations

Ques. 2JEE Main 2026, 6 April (Evening Shift)

A spring stretches by 2 mm when it is loaded with a mass of 200 g. From equilibrium position the mass is further pulled down by 2 mm and released. The frequency associated with the system and maximum energy in the spring are Hz and J, respectively. (Take g = 10 m/s2)

  1. 5 50 and 8 10-3
  2. 5 50 and 8
  3. 10 50 and 2 10-3
  4. 5 50 and 16 10-3
Ques. 3JEE Main 2026, 5 April (Evening Shift)

Match List-I with List-II. Choose the correct answer from the options given below :

  1. A-III, B-I, C-IV, D-II
  2. A-II, B-I, C-III, D-IV
  3. A-III, B-II, C-IV, D-I
  4. A-II, B-I, C-IV, D-III
Ques. 4JEE Main 2026, 4 April (Morning Shift)

The velocity of a particle executing simple harmonic motion along x-axis is described as v2=50-x2, where x represents displacement. If the time period of motion is x7 s, the value of x is .

Ques. 5JEE Main 2026, 4 April (Evening Shift)

A uniform disc of radius R and mass M is free to oscillate about the axis A as shown in the figure. For small oscillations the time period is . (g is acceleration due to gravity) [figure]

  1. 2 5R4g
  2. 2 2R3g
  3. 2 3R2g
  4. 2 3Rg
Ques. 6JEE Main 2026, 2 April (Evening Shift)

The equation of motion of a particle is given by x=a (50t+ /3) cm. The particle will come to rest at time t1 and it will have zero acceleration at time t2. The t1 and t2 respectively are .

  1. 300 s, 75 s
  2. 75 s, 300 s
  3. 300 s, 25 s
  4. 50 s, 100 s
Ques. 7JEE Main 2026, 28 January (Morning Shift)

The displacement of a particle, executing simple harmonic motion with time period T, is expressed as x(t) = A t, where A is the amplitude. The maximum value of potential energy of this oscillator is found at t = T/2 . The value of is .

Ques. 8JEE Main 2026, 28 January (Evening Shift)

As shown in the figure, a spring is kept in a stretched position with some extension by holding the masses 1 kg and 0.2 kg with a separation more than spring natural length and are released. Assuming the horizontal surface to be frictionless, the angular frequency (in SI unit) of the system is : [figure]

  1. 20
  2. 5
  3. 30
  4. 27
Ques. 9JEE Main 2026, 24 January (Morning Shift)

A cylindrical block of mass M and area of cross section A is floating in a liquid of density and with its axis vertical. When depressed a little and released the block starts oscillating. The period of oscillation is

  1. 2 AMg
  2. 2M Ag
  3. 2 M Ag
  4. AMg
Ques. 10JEE Main 2026, 24 January (Morning Shift)

A spring of force constant 15 N/m is cut into two pieces. If the ratio of their lengths is 1 : 3, then the force constant of smaller piece is N/m.

  1. 20
  2. 45
  3. 60
  4. 15
Ques. 11JEE Main 2026, 23 January (Morning Shift)

A simple pendulum of string length 30 cm performs 20 oscillations in 10 s. The length of the string required for the pendulum to perform 40 oscillations in the same time duration is cm. [Assume that the mass of the pendulum remains same.]

  1. 0.75
  2. 7.5
  3. 15
  4. 120

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