The equation of motion of a particle is given by x=a (50t+ /3) cm. The particle will come to rest at time t1 and it will have zero acceleration at time t2. The t1 and t2 respectively are .
- 300 s, 75 s
- 75 s, 300 s
- 300 s, 25 s
- 50 s, 100 s
Answer
(1) 300 s, 75 s
Solution
v = dxdt = 50a (50t + /3), which is zero for the first time when 50t1 + 3 = 2, so
50t1 = 6 t1 = 300 s
The acceleration is - 2x = -2500a (50t + /3), which is zero for the first time after t = 0 when 50t2 + 3 = , so
50t2 = 2 3 t2 = 2 150 = 75 s
Answer: (1)