A metal rod of length L rotates about one end at origin with a uniform angular velocity . The magnetic field radially falls off as B(r)=B0e- r; being a positive constant. The emf induced (neglecting the centripetal force on electrons in the rod) is :
- B0 [ 1 2-e- L ( 1 2+ L ) ]
- B0 [ 1 2+e- L ( 1 2+ L ) ]
- B0 [ 4 2-e-2 L ( 1 2+ 2L ) ]
- B0 [ 3 2-e-3 L ( 3 2+ L ) ]
Answer
(1) B0 [ 1 2-e- L ( 1 2+ L ) ]
Solution
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The element dr at distance r from O moves with speed v = r, so
d = B(r) v dr = B0e- r r dr
= B0 0L re- r dr
Integrating by parts, re- rdr = - re- r - e- r 2, so
= B0 [- re- r - e- r 2 ]0L
= B0 [ (- Le- L - e- L 2 ) - (0 - 1 2 ) ]
= B0 [ 1 2 - e- L ( 1 2 + L ) ]
Answer: (1)