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Kinetic Theory

JEE Main 2025 (Online) 2nd April Evening ShiftNumericalMedium📈 Topic in 3% papers+4
Ques. 1JEE Main 2025, 2 April (Evening Shift)

The internal energy of air in 4 m 4 m 3 m sized room at 1 atmospheric pressure will be 106 J (Consider air as diatomic molecule)

Answer

12

Solution

Diatomic gas: f = 5 U = f2nRT = 52PV

V = 4 4 3 = 48 m3, P = 1 atm = 1.013 105 Pa

U = 52 1.013 105 48

= 1.216 107 J 12 106 J

Answer: 12

Keep practising — Kinetic Theory

Ques. 2JEE Main 2025, 29 January (Morning Shift)

A container of fixed volume contains a gas at 27 . To double the pressure of the gas, the temperature of gas should be raised to .

Ques. 3JEE Main 2025, 28 January (Morning Shift)

For a particular ideal gas which of the following graphs represents the variation of mean squared velocity of the gas molecules with temperature?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]
Ques. 4JEE Main 2025, 28 January (Evening Shift)

The ratio of vapour densities of two gases at the same temperature is 425, then the ratio of r.m.s. velocities will be :

  1. 52
  2. 254
  3. 425
  4. 25
Ques. 5JEE Main 2025, 28 January (Evening Shift)

The kinetic energy of translation of the molecules in 50 g of CO2 gas at 17 is :

  1. 4205.5 J
  2. 3582.7 J
  3. 3986.3 J
  4. 4102.8 J
Ques. 6JEE Main 2025, 22 January (Evening Shift)

For a diatomic gas, if 1= ( CpCv ) for rigid molecules and 2= ( CpCv ) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct? (Cp and Cv are specific heats of the gas at constant pressure and volume)

  1. 2< 1
  2. 2> 1
  3. 2= 1
  4. 2 2= 1

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