Kinetic Theory

JEE Main 2025 (Online) 28th January Evening ShiftMCQEasy📈 Topic in 13% papers+4−1

Ques. 1JEE Main 2025, 28 January (Evening Shift)

The kinetic energy of translation of the molecules in 50 g of CO2 gas at 17 is :

4205.5 J
3582.7 J
3986.3 J
4102.8 J

Answer

(4) 4102.8 J

Solution

Number of moles: n = 5044 mol (molar mass of CO2 = 44 g mol-1)

T = 17 + 273 = 290 K

Translational KE: E = 32nRT

E = 32 5044 8.3 290 (taking R = 8.3 J mol-1 K-1)

E 4102.8 J

Answer: (4)

Keep practising — Kinetic Theory

Ques. 2JEE Main 2025, 22 January (Evening Shift)

For a diatomic gas, if 1= ( CpCv ) for rigid molecules and 2= ( CpCv ) for another diatomic molecules, but also having vibrational modes. Then, which one of the following options is correct? (Cp and Cv are specific heats of the gas at constant pressure and volume)

2< 1
2> 1
2= 1
2 2= 1

All Kinetic Theory PYQs →

PDFDownload Kinetic Theory PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇

All JEE Main Physics chapters

Class 11Units and Measurements Motion in a Straight Line Motion in a Plane Laws of Motion Work, Energy and Power System of Particles and Rotational Motion Gravitation Mechanical Properties of Solids Mechanical Properties of Fluids Thermal Properties of Matter Thermodynamics (Physics)Kinetic Theory Oscillations Waves

Class 12Electric Charges and Fields Electrostatic Potential and Capacitance Current Electricity Moving Charges and Magnetism Magnetism and Matter Electromagnetic Induction Alternating Current Electromagnetic Waves Ray Optics and Optical Instruments Wave Optics Dual Nature of Radiation and Matter Atoms Nuclei Semiconductor Electronics Experimental Skills (Physics)