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Application of Derivatives

Previous year questions with solutions · 2025 – 2026

25Questions
25Papers covered
2.53%Weightage 2026▼ 7.7% vs last year
Year-wise statistics questions · papers · average per paper · weightage
YearQuestionsPapersAvg / paperWeightage
202612190.632.53% ▼ 7.7% vs last year
202513190.682.74%

21 questions · newest paper first

Ques. 1JEE Main 2026, 8 April (Evening Shift)

For the function f(x)=e |x|-|x|, x R, consider the following statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true
Ques. 2JEE Main 2026, 6 April (Evening Shift)

Let A= bmatrix1 & 3 & -1\ 2 & 1 & \ 0 & 1 & -1 bmatrix be a singular matrix. Let f(x)= 0x (t2+2t+3 )dt, x [1, ]. If M and m are respectively the maximum and the minimum values of f in [1, ], then 3(M-m) is equal to :

  1. 64
  2. 68
  3. 72
  4. 76
Ques. 3JEE Main 2026, 5 April (Morning Shift)

Let f : R R be a differentiable function such that f ( x+y3 )= f(x)+f(y)3 for all x, y R, and f'(0)=3. Then the minimum value of the function g(x)=3+ex f(x), is:

  1. 3 ( e+1e )
  2. 3 ( e-1e )
  3. 3-ee
  4. 3e
Ques. 4JEE Main 2026, 4 April (Evening Shift)

0 x (16 ( x2 ) 3 ( x2 ) ) is equal to :

  1. 3 32
  2. 3 3
  3. 4 3
  4. 6 3
Ques. 5JEE Main 2026, 2 April (Morning Shift)

The number of critical points of the function f(x)= cases | xx |, & x 0\ 1, & x=0 cases in the interval (-2 , 2 ) is equal to :

  1. 1
  2. 3
  3. 5
  4. 7
Ques. 6JEE Main 2026, 2 April (Evening Shift)

Let f(x) be a polynomial of degree 5, and have extrema at x=1 and x=-1. If x 0 ( f(x)x3 )=-5, then f(2)-f(-2) is equal to:

  1. 0
  2. 50
  3. 92
  4. 112
Ques. 7JEE Main 2026, 24 January (Evening Shift)

Consider the following three statements for the function f : (0, ) R defined by f(x) = | e x| - |x - 1| : (I) f is differentiable at all x > 0. (II) f is increasing in (0, 1). (III) f is decreasing in (1, ). Then

  1. Only (I) is TRUE.
  2. Only (I) and (III) are TRUE.
  3. Only (II) and (III) are TRUE.
  4. All (I), (II) and (III) are TRUE.
Ques. 8JEE Main 2026, 22 January (Morning Shift)

Let f(x) = x2025 - x2000, x [0, 1] and the minimum value of the function f(x) in the interval [0, 1] be (80)80(n)-81. Then n is equal to

  1. -40
  2. -41
  3. -80
  4. -81
Ques. 9JEE Main 2026, 21 January (Evening Shift)

Let f : R R be a twice differentiable function such that f''(x) > 0 for all x R and f'(a - 1) = 0, where a is a real number. Let g(x) = f( 2 x - 2 x + a), 0 < x < 2. Consider the following two statements: (I) g is increasing in (0, 4 ) (II) g is decreasing in ( 4, 2 ) Then,

  1. Both (I) and (II) are True
  2. Neither (I) nor (II) is True
  3. Only (I) is True
  4. Only (II) is True
Ques. 10JEE Main 2025, 8 April (Evening Shift)

Let the function f(x) = x3 + 3x + 3, x 0 be strictly increasing in (- , 1) ( 2, ) and strictly decreasing in ( 3, 4) ( 4, 5). Then i=15 i2 is equal to

  1. 48
  2. 40
  3. 36
  4. 28
Ques. 11JEE Main 2025, 7 April (Morning Shift)

Let x = -1 and x = 2 be the critical points of the function f(x) = x3 + ax2 + b e |x| + 1, x 0. Let m and M respectively be the absolute minimum and the absolute maximum values of f in the interval [-2, - 12 ]. Then |M + m| is equal to (Take e 2 = 0.7):

  1. 21.1
  2. 19.8
  3. 22.1
  4. 20.9
Ques. 12JEE Main 2025, 7 April (Evening Shift)

Let f : R R be a polynomial function of degree four having extreme values at x = 4 and x = 5. If x 0 f(x)x2 = 5, then f(2) is equal to :

  1. 8
  2. 10
  3. 12
  4. 14
Ques. 13JEE Main 2025, 4 April (Evening Shift)

Let a > 0. If the function f(x) = 6x3 - 45ax2 + 108a2x + 1 attains its local maximum and minimum values at the points x1 and x2 respectively such that x1 x2 = 54, then a + x1 + x2 is equal to :

  1. 15
  2. 13
  3. 24
  4. 18
Ques. 14JEE Main 2025, 3 April (Evening Shift)

Let f : R R be a function defined by f(x) = ||x + 2| - 2|x| |. If m is the number of points of local minima and n is the number of points of local maxima of f, then m + n is

  1. 3
  2. 4
  3. 2
  4. 5
Ques. 15JEE Main 2025, 2 April (Morning Shift)

If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, where a > 0, attains its local maximum and local minimum values at p and q, respectively, such that p2 = q, then f(3) is equal to :

  1. 55
  2. 37
  3. 10
  4. 23
Ques. 16JEE Main 2025, 29 January (Evening Shift)

Let f(x)= 0x t (t2-9t+20 )dt, 1 x 5. If the range of f is [ , ], then 4( + ) equals :

  1. 253
  2. 157
  3. 154
  4. 125
Ques. 17JEE Main 2025, 28 January (Morning Shift)

The sum of all local minimum values of the function f(x) = cases 1 - 2x, & x < -1 \ 13(7 + 2|x|), & -1 x 2 \ 1118(x - 4)(x - 5), & x > 2 cases is

  1. 16772
  2. 15772
  3. 17172
  4. 13172
Ques. 18JEE Main 2025, 24 January (Morning Shift)

Consider the region R= \(x,y):x y 9- 113x2, x 0 \. The area of the largest rectangle of sides parallel to the coordinate axes and inscribed in R, is:

  1. 821123
  2. 567121
  3. 730119
  4. 625111
Ques. 19JEE Main 2025, 24 January (Evening Shift)

Let (2,3) be the largest open interval in which the function f(x)=2 e(x-2)-x2+ax+1 is strictly increasing and (b,c) be the largest open interval, in which the function g(x)=(x-1)3(x+2-a)2 is strictly decreasing. Then 100(a+b-c) is equal to :

  1. 360
  2. 420
  3. 160
  4. 280
Ques. 20JEE Main 2025, 23 January (Evening Shift)

A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm, the ice-cream melts at the rate of 81 cm3/min and the thickness of the ice-cream layer decreases at the rate of 14 cm/min. The surface area (in cm2) of the chocolate ball (without the ice-cream layer) is :

  1. 128
  2. 196
  3. 225
  4. 256
Ques. 21JEE Main 2025, 22 January (Evening Shift)

Let f(x)= 0x2 t2-8t+15et dt, x . Then the numbers of local maximum and local minimum points of f, respectively, are :

  1. 3 and 2
  2. 2 and 2
  3. 2 and 3
  4. 1 and 3