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Application of Derivatives

JEE Main 2026 (Online) 8th April Evening ShiftMCQMedium📈 Topic in 16% papers+4−1
Ques. 1JEE Main 2026, 8 April (Evening Shift)

For the function f(x)=e |x|-|x|, x R, consider the following statements : In the light of the above statements, choose the correct answer from the options given below :

  1. Both Statement I and Statement II are true
  2. Both Statement I and Statement II are false
  3. Statement I is true but Statement II is false
  4. Statement I is false but Statement II is true

Answer

(1) Both Statement I and Statement II are true

Solution

For x 0: f(x)=e x-x f'(x)= x e x-1

For x<0: |x|=- x, |x|=-x f(x)=e- x+x f'(x)=1- x e- x

Both pieces are differentiable, so only x=0 needs checking:

f'(0+)=1 e0-1=0, f'(0-)=1-1 e0=0

f'(0+)=f'(0-)=0 (the corners of e |x| and -|x| at 0 cancel)

f is differentiable for all x Statement I is true

For x (- , - 2 ): x<0 and e- x>0

f'(x)=1- x e- x>1>0

f is increasing in (- , - 2 ) Statement II is true

Answer: (1)

Keep practising — Application of Derivatives

Ques. 2JEE Main 2026, 6 April (Evening Shift)

Let A= bmatrix1 & 3 & -1\ 2 & 1 & \ 0 & 1 & -1 bmatrix be a singular matrix. Let f(x)= 0x (t2+2t+3 )dt, x [1, ]. If M and m are respectively the maximum and the minimum values of f in [1, ], then 3(M-m) is equal to :

  1. 64
  2. 68
  3. 72
  4. 76
Ques. 3JEE Main 2026, 5 April (Morning Shift)

Let f : R R be a differentiable function such that f ( x+y3 )= f(x)+f(y)3 for all x, y R, and f'(0)=3. Then the minimum value of the function g(x)=3+ex f(x), is:

  1. 3 ( e+1e )
  2. 3 ( e-1e )
  3. 3-ee
  4. 3e
Ques. 4JEE Main 2026, 4 April (Evening Shift)

0 x (16 ( x2 ) 3 ( x2 ) ) is equal to :

  1. 3 32
  2. 3 3
  3. 4 3
  4. 6 3
Ques. 5JEE Main 2026, 2 April (Morning Shift)

The number of critical points of the function f(x)= cases | xx |, & x 0\ 1, & x=0 cases in the interval (-2 , 2 ) is equal to :

  1. 1
  2. 3
  3. 5
  4. 7
Ques. 6JEE Main 2026, 2 April (Evening Shift)

Let f(x) be a polynomial of degree 5, and have extrema at x=1 and x=-1. If x 0 ( f(x)x3 )=-5, then f(2)-f(-2) is equal to:

  1. 0
  2. 50
  3. 92
  4. 112
Ques. 7JEE Main 2026, 28 January (Evening Shift)

Let f be a differentiable function satisfying f(x) = 1 - 2x + 0x e(x-t) f(t) dt, x R and let g(x) = 0x (f(t) + 2)15(t - 4)6(t + 12)17 dt, x R. If p and q are respectively the points of local minima and local maxima of g, then the value of |p + q| is equal to .

Ques. 8JEE Main 2026, 24 January (Morning Shift)

Let (2 , ) be the largest interval in which the function f(t) = |t+1|t2, t < 0, is strictly decreasing. Then the local maximum value of the function g(x) = 2 e(x-2) + x2 + 4x - , x > 2, is

Ques. 9JEE Main 2026, 24 January (Evening Shift)

Consider the following three statements for the function f : (0, ) R defined by f(x) = | e x| - |x - 1| : (I) f is differentiable at all x > 0. (II) f is increasing in (0, 1). (III) f is decreasing in (1, ). Then

  1. Only (I) is TRUE.
  2. Only (I) and (III) are TRUE.
  3. Only (II) and (III) are TRUE.
  4. All (I), (II) and (III) are TRUE.
Ques. 10JEE Main 2026, 22 January (Morning Shift)

Let f(x) = x2025 - x2000, x [0, 1] and the minimum value of the function f(x) in the interval [0, 1] be (80)80(n)-81. Then n is equal to

  1. -40
  2. -41
  3. -80
  4. -81
Ques. 11JEE Main 2026, 21 January (Morning Shift)

Let f : R R be a twice differentiable function such that the quadratic equation f(x)m2 - 2f'(x)m + f''(x) = 0 in m, has two equal roots for every x R. If f(0) = 1, f'(0) = 2, and ( , ) is the largest interval in which the function f( e x - x) is increasing, then + is equal to .

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