Application of Derivatives

Let (2,3) be the largest open interval in which the function f(x)=2 e(x-2)-x2+ax+1 is strictly increasing and (b,c) be the largest open interval, in which the function g(x)=(x-1)3(x+2-a)2 is strictly decreasing. Then 100(a+b-c) is equal to :

1. 360
2. 420
3. 160
4. 280

If the set of all values of a, for which the equation 5x3-15x-a=0 has three distinct real roots, is the interval ( , ), then -2 is equal to .

A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm, the ice-cream melts at the rate of 81 cm3/min and the thickness of the ice-cream layer decreases at the rate of 14 cm/min. The surface area (in cm2) of the chocolate ball (without the ice-cream layer) is :

1. 128
2. 196
3. 225
4. 256

Let f(x)= 0x2 t2-8t+15et dt, x . Then the numbers of local maximum and local minimum points of f, respectively, are :

1. 3 and 2
2. 2 and 2
3. 2 and 3
4. 1 and 3

Let the set of all positive values of , for which the point of local minimum of the function (1 + x ( 2 - x2 ) ) satisfies x2 + x + 2x2 + 5x + 6 < 0, be ( , ). Then 2 + 2 is equal to .

Let the set of all values of p, for which f(x) = (p2 - 6p + 8 ) ( 2 2x - 2 2x ) + 2(2 - p)x + 7 does not have any critical point, be the interval (a, b). Then 16ab is equal to .

Let f(x) = 4 3 x + 3 3 2 x - 10. The number of points of local maxima of f in interval (0, 2 ) is

1. 1
2. 3
3. 4
4. 2

The number of critical points of the function f(x) = (x - 2)2/3(2x + 1) is

1. 2
2. 1
3. 0
4. 3

For the function f(x) = ( x) - x + 1, x R, between the following two statements (S1) f(x) = 0 for only one value of x in [0, ]. (S2) f(x) is decreasing in [0, 2 ] and increasing in [ 2, ].

1. Both (S1) and (S2) are incorrect.
2. Only (S1) is correct.
3. Only (S2) is correct.
4. Both (S1) and (S2) are correct.

If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, a > 0 has a local maximum at x = and a local minimum at x = 2, then and 2 are the roots of the equation :

1. x2 - 6x + 8 = 0
2. 8x2 - 6x + 1 = 0
3. 8x2 + 6x - 1 = 0
4. x2 + 6x + 8 = 0