Atomos Test Generator Free PYQs ExamsMy practice Log in / Sign up free

Application of Derivatives

JEE Main 2025 (Online) 23rd January Evening ShiftMCQRank Booster📈 Topic in 2% papers+4−1
Ques. 1JEE Main 2025, 23 January (Evening Shift)

A spherical chocolate ball has a layer of ice-cream of uniform thickness around it. When the thickness of the ice-cream layer is 1 cm, the ice-cream melts at the rate of 81 cm3/min and the thickness of the ice-cream layer decreases at the rate of 14 cm/min. The surface area (in cm2) of the chocolate ball (without the ice-cream layer) is :

  1. 128
  2. 196
  3. 225
  4. 256

Answer

(4) 256

Solution

Only the ice-cream shrinks: V= 43 (R3-r3) with r fixed.

[figure]

dVdt=4 R2 dRdt 81=4 R2 14 R=9

r=R-1=8 cm

Surface area = 4 r2=256 cm2

Answer: (4)

Keep practising — Application of Derivatives

Ques. 2JEE Main 2025, 22 January (Evening Shift)

Let f(x)= 0x2 t2-8t+15et dt, x . Then the numbers of local maximum and local minimum points of f, respectively, are :

  1. 3 and 2
  2. 2 and 2
  3. 2 and 3
  4. 1 and 3
Ques. 3JEE Main 2024, 9 April (Morning Shift)

Let the set of all positive values of , for which the point of local minimum of the function (1 + x ( 2 - x2 ) ) satisfies x2 + x + 2x2 + 5x + 6 < 0, be ( , ). Then 2 + 2 is equal to .

Ques. 4JEE Main 2024, 9 April (Evening Shift)

Let the set of all values of p, for which f(x) = (p2 - 6p + 8 ) ( 2 2x - 2 2x ) + 2(2 - p)x + 7 does not have any critical point, be the interval (a, b). Then 16ab is equal to .

Ques. 5JEE Main 2024, 8 April (Morning Shift)

Let f(x) = 4 3 x + 3 3 2 x - 10. The number of points of local maxima of f in interval (0, 2 ) is

  1. 1
  2. 3
  3. 4
  4. 2
Ques. 6JEE Main 2024, 8 April (Morning Shift)

The number of critical points of the function f(x) = (x - 2)2/3(2x + 1) is

  1. 2
  2. 1
  3. 0
  4. 3
Ques. 7JEE Main 2024, 8 April (Morning Shift)

For the function f(x) = ( x) - x + 1, x R, between the following two statements (S1) f(x) = 0 for only one value of x in [0, ]. (S2) f(x) is decreasing in [0, 2 ] and increasing in [ 2, ].

  1. Both (S1) and (S2) are incorrect.
  2. Only (S1) is correct.
  3. Only (S2) is correct.
  4. Both (S1) and (S2) are correct.
Ques. 8JEE Main 2024, 8 April (Evening Shift)

If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, a > 0 has a local maximum at x = and a local minimum at x = 2, then and 2 are the roots of the equation :

  1. x2 - 6x + 8 = 0
  2. 8x2 - 6x + 1 = 0
  3. 8x2 + 6x - 1 = 0
  4. x2 + 6x + 8 = 0
Ques. 9JEE Main 2024, 8 April (Evening Shift)

Let A be the region enclosed by the parabola y2 = 2x and the line x = 24. Then the maximum area of the rectangle inscribed in the region A is .

Ques. 10JEE Main 2024, 6 April (Morning Shift)

The interval in which the function f(x) = xx, x > 0, is strictly increasing is

  1. (0, )
  2. (0, 1e ]
  3. [ 1e2, 1 )
  4. [ 1e, )
Ques. 11JEE Main 2024, 6 April (Evening Shift)

If the function f(x) = ( 1x )2x; x > 0 attains the maximum value at x = 1e then :

  1. e < e
  2. e2 < (2 )e
  3. (2e) > (2e)
  4. e > e

All Application of Derivatives PYQs →

PDFDownload Application of Derivatives PYQs as PDF Free, with answer key and a QR code to every solution — print it or study offline⬇
All JEE Main Mathematics chapters