If the function f(x) = 2x3 - 9ax2 + 12a2x + 1, a > 0 has a local maximum at x = and a local minimum at x = 2, then and 2 are the roots of the equation :
- x2 - 6x + 8 = 0
- 8x2 - 6x + 1 = 0
- 8x2 + 6x - 1 = 0
- x2 + 6x + 8 = 0
Answer
(1) x2 - 6x + 8 = 0
Solution
f'(x) = 6x2 - 18ax + 12a2 = 6(x - a)(x - 2a)
∵ a > 0: f' changes sign + - at x = a (max) and - + at x = 2a (min)
= a and 2 = 2a a2 = 2a a = 2
roots 2 and 4: sum = 6, product = 8
∴ Required equation: x2 - 6x + 8 = 0
Answer: (1)