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JEE Main 2025 (Online) 24th January Morning ShiftMCQMedium📈 Topic in 11% papers+4−1
Ques. 1JEE Main 2025, 24 January (Morning Shift)

Consider the given plots of vapour pressure (VP) vs temperature (T/K). Which amongst the following options is correct graphical representation showing Tf, depression in the freezing point of a solvent in a solution?

  1. [figure]
  2. [figure]
  3. [figure]
  4. [figure]

Answer

(3) [figure]

Solution

Non-volatile solute the solution curve lies BELOW the liquid-solvent curve.

Freezing point = where a liquid curve meets the frozen curve; the solution meets it at the lower Tf Tf=Tf -Tf.

Only (3) shows this.

Answer: (3)

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Ques. 2JEE Main 2025, 24 January (Evening Shift)

The observed and normal molar masses of compound MX2 are 65.6 and 164 respectively. The percent degree of ionisation of MX2 is %. (Nearest integer)

Ques. 3JEE Main 2025, 23 January (Morning Shift)

CrCl3 xNH3 can exist as a complex. 0.1 molal aqueous solution of this complex shows a depression in freezing point of 0.558 C. Assuming 100% ionisation of this complex and coordination number of Cr is 6, the complex will be (Given Kf = 1.86 K kg mol-1)

  1. [Cr(NH3)5Cl]Cl2
  2. [Cr(NH3)4Cl2]Cl
  3. [Cr(NH3)6]Cl3
  4. [Cr(NH3)3Cl3]
Ques. 4JEE Main 2025, 23 January (Evening Shift)

When a non-volatile solute is added to the solvent, the vapour pressure of the solvent decreases by 10 mm of Hg. The mole fraction of the solute in the solution is 0.2. What would be the mole fraction of the solvent if decrease in vapour pressure is 20 mm of Hg ?

  1. 0.2
  2. 0.4
  3. 0.8
  4. 0.6
Ques. 5JEE Main 2025, 23 January (Evening Shift)

Consider a binary solution of two volatile liquid components 1 and 2. x1 and y1 are the mole fractions of component 1 in liquid and vapour phase, respectively. The slope and intercept of the linear plot of 1x1 vs 1y1 are given respectively as :

  1. P10P20, P10-P20P20
  2. P20P10, P20-P10P10
  3. P20P10, P10-P20P20
  4. P10P20, P20-P10P20
Ques. 6JEE Main 2025, 22 January (Morning Shift)

Arrange the following solutions in order of their increasing boiling points. (i) 10-4 M NaCl (ii) 10-4 M Urea (iii) 10-3 M NaCl (iv) 10-2 M NaCl

  1. (i) < (ii) < (iii) < (iv)
  2. (ii) < (i) < (iii) < (iv)
  3. (iv) < (iii) < (i) < (ii)
  4. (ii) < (i) (iii) < (iv)
Ques. 7JEE Main 2025, 22 January (Evening Shift)

Density of 3 M NaCl solution is 1.25 g/mL. The molality of the solution is :

  1. 2.79 m
  2. 2 m
  3. 1.79 m
  4. 3 m

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