[figure] For the circuit shown above, equivalent GATE is :
- NOT gate
- NAND gate
- AND gate
- OR gate
Answer
(4) OR gate
Solution
The upper NAND gate gives Y1 = A B and the NOR gate gives Y2 = A + B.
The final NAND gate then gives Y = Y1 Y2 = Y1 + Y2 (De Morgan), so
Y = A B + (A + B)
Y = A + B (absorption: AB + A = A)
the circuit is equivalent to an OR gate.
Answer: (4)