A parallel plate capacitor of capacitance 1 μF is charged to a potential difference of 20 V. The distance between plates is 1 μm. The energy density between plates of capacitor is :
- 1.8 103 J/m3
- 2 102 J/m3
- 2 10-4 J/m3
- 1.8 105 J/m3
Answer
(1) 1.8 103 J/m3
Solution
The field between the plates is E = Vd = 2010-6 = 2 107 V/m, and the energy density is u = 12 0 E2, so
u = 12 8.85 10-12 (2 107)2
u = 1.77 103 1.8 103 J/m3
Answer: (1)