A light hollow cube of side length 10 cm and mass 10 g, is floating in water. It is pushed down and released to execute simple harmonic oscillations. The time period of oscillations is y 10-2 s, where the value of y is (Acceleration due to gravity, g=10 m/s2, density of water =103 kg/m3 )
- 2
- 4
- 1
- 6
Answer
(1) 2
Solution
Pushed down by x, the extra upthrust is the restoring force: F=- Ag x, so k= Ag (SHM).
[figure]
k=103 10-2 10=100 N m-1, m=10-2 kg
T=2 mk=2 10-2 s y=2
Answer: (1)